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2 years ago

Human activities that impact the water cycle

Physics

1 answer:

xeze [42]2 years ago

3 0

Answer:

Explanation:

A number of human activities can impact on the water cycle: damming rivers for hydroelectricity, using water for farming, deforestation and the burning of fossil fuels.

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Inga [223]

Answer is c, they are equal:

Explanation:

4 0

2 years ago

An object is moving at 2.50 m/s [E]. At a time 3.00 seconds later the object is traveling at 1.50 m/s

babunello [35]

Given parameters:

First velocity = 2.50m/s

Time of travel = 3s

Second velocity = 1.50m/s

Unknown:

The displacement during the first interval = ?

Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.

Velocity = $\frac{Displacement}{Time taken}$

So;

Displacement = Velocity x Time taken

Now input the parameter for the first velocity and time of travel;

Displacement = 2.5 x 3 = 7.5m

The displacement id 7.5m

7 0

2 years ago

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan

Elan Coil [88]

Answer:

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous planet increases linearly with the height of the atmosphere as measured from the top of a visible boundary layer, defined as 0 kilometers in altitude. The instruments on board can withstand a temperature of 601 K. At what altitude will the probe's instruments fail? A. 50 kilometers B. 80 kilometers C. 83 kilometers D. 100 kilometers E. 111 kilometers

Explanation:

A. 50 kilometers

8 0

2 years ago

A human hair is approximately 50 pm in diameter. Express this diameter in meters.

cupoosta [38]

A human hair is approximately 50 μm = 5 × 10⁻⁵ m in diameter

4 0

2 years ago

A uniformly charged, straight filament 5.10 m in length has a total positive charge of 2.00 µC. An uncharged cardboard cylinder

Ratling [72]

Answer:

70509.8039216 N/C

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

q = Charge = 2.00 µC

l = Length of filament = 5.1 m

r = Radius of cylinder = 10 cm

$\lambda=\dfrac{q}{l}$

Electric field is given by

$E=\dfrac{2k\lambda}{r}\\\Rightarrow E=\dfrac{2\times 8.99\times 10^9\times \dfrac{2\times 10^{-6}}{5.1}}{10\times 10^{-2}}\\\Rightarrow E=70509.8039216\ N/C$

The electric field at the surface of the cylinder is 70509.8039216 N/C

7 0

2 years ago

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