Ho123 right I’m sorry of I’m wrong
<span>Classify is the answer hope this helps :)</span>
the answer is B because I jus did that
Answer:
2.82 L
T₁ = 303 K
T₂ = 263 K
The final volume is smaller.
Explanation:
Step 1: Given data
- Initial temperature (T₁): 30 °C
- Initial volume (V₁): 3.25 L
- Final temperature (T₂): -10 °C
Step 2: Convert the temperatures to Kelvin
We will use the following expression.
K = °C + 273.15
T₁: K = 30°C + 273.15 = 303 K
T₂: K = -10°C + 273.15 = 263 K
Step 3: Calculate the final volume of the balloon
Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.
V₁/T₁ = V₂/T₂
V₂ = V₁ × T₂/T₁
V₂ = 3.25 L × 263 K/303 K = 2.82 L
We know that [OH⁻] * [H⁺] = 10⁻¹⁴
plugging the value of [H⁺]
[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ * (10³/1.2)
[OH⁻] = 833.3 * 10⁻¹⁴
[OH⁻] = 8.33 * 10⁻¹²
