The empirical formula of this compound is
<u>Given the following data:</u>
<u>Scientific data:</u>
- Molar mass of hydrogen (H) = 1.0 g/mol.
- Molar mass of sulfur (S) = 32 g/mol.
- Molar mass of oxygen (O) = 16 g/mol.
To determine the empirical formula of this compound:
Note: We would assume that the mass of the compound is 100 grams.
Hence, the mass of its constituent elements are:
- Mass of hydrogen (H) = 2.00 grams
- Mass of sulfur (S) = 32.7 grams
- Mass of oxygen (O) = 65.3 grams
Next, we would determine the number of moles of each element by using this formula:
<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>
Number of moles = 2.0 moles
<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>
Number of moles = 1.0 moles
<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>
Number of moles = 4.0 moles
Empirical formula =
Read more: brainly.com/question/21280037
Answer:
- NH₄CN,
- NH₄ClO₃,
- (NH₄)₂SO₃,
- NH₄H₂PO₄.
- Al(CN)₃,
- Al(ClO₃)₃,
- Al₃(SO₃)₃,
- Al(H₂PO₄)₃.
Explanation:
Cations (positive ions) and anions (negative ions) combine to form ionic compounds. The charge of each ion is stated as the superscript in its formula.
The final compounds should be neutral (not carrying charge.) For that to happen, the ions should combine at a ratio that allows their charges to balance.
By convention, in chemical formula of ionic compounds, cations are written before anions.
<h3>Example: Al³⁺ and SO₃²⁻</h3>
The charge on an Al³⁺ cation is +3. The charge on a SO₃²⁻ anion is -2.
Start by finding the least common multiple of the absolute value of the charges (drop the negative sign in front of the charge.)
.
The number of Al³⁺ ions in a formula unit of this compound will be equal to
.
Similarly, the number of SO₃²⁻ ions in a formula unit of this compound will be equal to
.
If a polyatomic ion (an ion with more than one atoms in it) appears more than once in the formula, enclose it in brackets and write the number of its occurrence outside the bracket.
.
Apply this rule to find the formula of other compounds. Additionally, keep in mind that if the charge on the cation and the anion is the same, each should occur only once in the formula.
Answer:
which elements??? more info please
Answer:
Neon
(if you want a thorough explanaion, just ask for one)
Answer:
The energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom is .
Absorption is taking place.
Explanation:
where,
= energy of orbit
n = number of orbit
Z = atomic number
Energy of n = 5 in an hydrogen atom:
Energy of n = 2 in an hydrogen atom:
Energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom = E
Positive value of energy means that absorption is taking place that electron excite from lower energy level to higher energy level by absorbing the energy.
E =
The energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom is .