All categories

4 years ago

Why do road crews spred sand over icey roads?

2 answers:

7 0

You mean Salt, right?

Salt helps remove ice from the roads, making is safer to drive on.

Putting Sand on roads would, if anything, make them even more dangerous.

Anvisha [2.4K]4 years ago

3 0

<span>Sand is used as a way to keep traction for the cars that pass through the streets. The sand works to keep cars on the roads and prevent any major accidents that may occur. </span>

You might be interested in

In a collision between two objects having unequal masses, how does magnitude of the impulse imparted to the lighter object by th

olasank [31]

<span>Both objects receive the same impulse.</span>

3 0

3 years ago

A 12.0kg microwave oven is pushed 14.0m up the sloping surface of a loading ramp inclined at an angle 37 degrees above the horiz

Semenov [28]

Answer:

Answered

Explanation:

a) What is the work done on the oven by the force F?

W = F * x

W = 120 N * (14.0 cos(37))

<<<< (x component)

W = 1341.71

b) $F_f=\mu_k N$

$F_f=0.25\times12\times9.8$

= 29.4 N

$W_f= F_f\times x$

$W_f= 29.0\times 14 cos(37)$

W_f= 328.72 J = 329 J

c) increase in the internal energy

U_2 = mgh

= 12*9.81*14sin(37)

= 991 J

d) the increase in oven's kinetic energy

U_1 + K_1 + W_other = U_2 + K_2

0 + 0 + (W_F - W_f ) = U_2 + K_2

1341.71 J - 329 J - 991 J = K_2

K_2 = 21.71 J

e) F - F_f = ma

(120N - 29.4N ) / 12.0kg = a

a = 7.55m/s^2

vf^2 = v0^2 + 2ax

vf^2 = 2(7.55m/s)(14.0m)

V_f = 14.5396m/s

K = 1/2(mv^2)

K = 1/2(12.0kg)(14.5396m/s)

K = 87.238J

4 0

3 years ago

At a pressure 43 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of t

Allisa [31]

P = 43 * 10^3
V = 12 L

P' =?
V' = 8 L

PV = P'V'
43*10^3* 12 = P' * 8

I know you can do it from here, mate ;)

7 0

3 years ago

A box is pulled up a rough ramp that makes an angle of 22

Svetradugi [14.3K]

Answer:

139 N

Explanation:

Thats the answer on e2020

3 0

3 years ago

What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of fricti

RideAnS [48]

Answer:

Maximum speed of the car is 26.56 m/s.

Explanation:

Given that,

Mass of the car, m = 1200 kg

Radius of the curve, r = 90 m

The coefficient of friction between tires and the road is 0.8.

We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

$\dfrac{v^2}{r}=\mu g\\\\v=\sqrt{\mu gr} \\\\v=\sqrt{0.8\times 9.8\times 90} \\\\v=26.56\ m/s$

So, the maximum speed of the car is 26.56 m/s.

5 0

4 years ago