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kirill [66]
3 years ago
5

What must you do to calculate a meaningful value of distance from the following equation?

Physics
2 answers:
ss7ja [257]3 years ago
5 0

Answer:

Convert all the times to either hours or seconds

Explanation:

One time unit is in hours, and the other is in seconds.  In order to do the math, the units need to be the same.  So you either need to convert hours to seconds, or seconds to hours.

devlian [24]3 years ago
4 0

Answer:

-Convert all the times to either hours or seconds.

Explanation:

Given,

d= (0.90km) + (12.5km/h) \times (31.5s)

While doing a mathematical calculation all the units should be same otherwise the result will not be correct. Here two units of time i.e. second and hour are being used. We will convert the second to hour by dividing it by 3600 as there are 3600 seconds in one hour. The distance will be,

d= (0.90km) + (12.5km/h) \times (\frac{31.5}{3600}h)

d= 0.90 + 12.5 \times \frac{31.5}{3600}

d= 0.90 + \frac{393.75}{3600}

d= 0.90 + 0.109

d= 1.009 km

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An object whose weight is 100lbf( pound force) experiences a decrease i kinetic energy of 500ft-lb, and an increase in potential
alexandr1967 [171]

Answer:

a) 35.75 ft/s

b) 45 ft

Explanation:

<u>Given  </u>

Weight W = 100 lbf

mass(m) = 100*32.174/32.2=99.92 lb

decrease in kinetic energy ΔKE = -500 ft.lbf

increase in kinetic energy ΔPE= 1500 ft.lbf

initial velocity V_1  = 40 ft/s

initial height h_1 = 30 ft/s

The gravitational acceleration g = 32.2 ft/s2 Required  

(a) Final velocity V_2 (a) Final elevation h_2  

<u>Solution </u>

Change in kinetic energy is defined by

ΔKE = .5*m *( V_2 ^2-V_1^2)

Change in potential energy is defined by

ΔKE = W *( h_2 -h_1 )

Then,

-500=.5*99.92*1/32.174*(V_2 ^2-40^2)

V_2=35.75 ft/s

1500 = 100 x (h_2  — 30)  

h_2= 45 ft

3 0
4 years ago
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Answer:0.8 meter

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