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3 years ago

In which direction does a Newton’s third law reaction force act?

Physics

2 answers:

Alinara [238K]3 years ago

8 0

<h2>Answer:</h2>

<u>The correct choice is </u><u>B. In the opposite direction from the action force </u>

<h2>Explanation:</h2>

According to Newtons 3rd law every action has a reaction which is equal in magnitude but opposite in the direction. The direction of the force on the first object is opposite to the direction of the force on the second object. In other words all forces between two objects exist in equal magnitude and opposite direction.

Mathematically

FA = −FB

Norma-Jean [14]3 years ago

6 0

<h2>Hello!</h2>

The answer is: B. In the opposite direction from the action force.

Newton's third law states that there is always a force acting in the opposite direction from the first applied force to an object, the second force will have the same magnitude but the opposite direction.

For example, when we sit on a chair, there is a force applied on the chair (our weight), at the same time, there is an equal force but with opposite direction going from the chair to us.

There are other two laws established by Newton, and they are related to the object's movement, acceleration, forces, masses, and velocity.

Have a nice day!

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¿que aceleracion producira una fuerza neta de 250N a un objeto de 20kg?

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Answer:

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3 years ago

A quantum system has three states, with energies 0, 1.6 × 10-21, and 1.6 × 10-21, in Joules. It is coupled to an environment wit

xenn [34]

To develop the problem it is necessary to apply two concepts, the first is related to the calculation of average data and the second is the Boltzmann distribution.

Boltzmann distribution is a probability distribution or probability measure that gives the probability that a system will be in a certain state as a function of that state's energy and the temperature of the system. It is given by

$z = \sum\limit_i e^{-\frac{\epsilon_i}{K_0T}}$

Where,

$\epsilon_i =$ energy of that state

k = Boltzmann's constant

T = Temperature

With our values we have that

T= 250K

$k = 1.381*10^{23} m^2 kg s^{-2} K^{-1}$

$\epsilon_1=0J$

$\epsilon_2=1.6*10^{-21}J$

$\epsilon_3=1.6*10^{-21}J$

To make the calculations easier we can assume that the temperature and Boltzmann constant can be summarized as

$\beta = \frac{1}{kT}$

$\beta = \frac{1}{(1.381*10^{23} m^2)(250)}$

$\beta = 2.9*10^{20}J$

Therefore the average energy would be,

$\bar{\epsilon} =\frac{\sum \epsilon_i e^{-\beta \epsilon_i}}{\sum e^{-\beta \epsilon_i}}$

Replacing with our values we have

$\bar{\epsilon} = \frac{0e^{-0}+1.6*10^{-21}*e^{-\Beta(1.6*10^{-21})}+1.6*10^{-2-1}*e^{-(2.9*10^{20})(1.6*10^{-21})}}{1+2e^{-2.9*10^{20}*1.6*10^{-21}}}$

$\bar{\epsilon} = 0.9*10^{-22}J$

Therefore the average internal energy is $\bar{\epsilon} = 0.9*10^{-22}J$

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3 years ago

All elements in the same group____

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Answer:

Explanation:

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3 years ago

How much heat is need to boil 120 kg of water

Slav-nsk [51]

Answer: The energy required to change water from a liquid to a solid is 333.7 kJ/kg while the energy required to boil water is 2257 kJ/kg. The amount of energy needed to change the phase of water to a gas from a liquid is 540 times the amount of energy needed to raise the same amount of water 1° C

Explanation:

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3 years ago

The outer surface of a skier’s clothes of emissivity 0.7000.700 is at a temperature of 5.505.50 °C. Find the rate of radiation i

Ludmilka [50]

Answer:

121.0 W

Explanation:

We use the equation for rate of heat transfer during radiation.

Q/t = σεA(T₂⁴ - T₁⁴)

Since temperature of surroundings = T₁ = -20.0°C = 273 +(-20) = 253 K, and temperature of skier's clothes = T₂ = 5.50°C = 273 + 5.50 = 278.5 K.

Surface area of skier , A = 1.60 m², emissivity of skier's clothes, ε = 0.70 and σ = 5.67 × 10⁻⁸ W/m²K⁴ .

Therefore, the rate of heat transfer by radiation Q/t is

Q/t = σεA(T₂⁴ - T₁⁴) = (5.67 × 10⁻⁸ W/m²K⁴ ) × 0.70 × 1.60 m² × (278.5⁴ - 253⁴) = 6.3054 × (1918750544.0625) × 10⁻⁸ W = 1.2098 × 10² W = 120.98 W ≅ 121.0 W

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3 years ago

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