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3 years ago

In your own words, explain Newton’s first law of motion.

2 answers:

5 0

Newton's first law of motion states that. an object on the rest or motion is stay the same unless external force applied on it.

Daniel [21]3 years ago

4 0

A object at rest will stay at rest and a object in motion will stay in motion unless acted upon by a external force. Hope this helps

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An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.270 rev/s . The magnitude

JulijaS [17]

Answer:

Given information is summarized as below:

$\omega _{o}=0.270rev/sec=1.69 rad/sec\\\alpha =0.895rev/sec=5.62rad/sec\\d=0.790m$

1)Using first equation of kinematics for angular motion we have

$\omega _{f}=\omega _{o}+\alpha t\\\\\therefore \omega _{f}=1.69+5.62\times 0.194\\\omega _{f}=2.780rad/sec$

2) Using second equation of kinematics for angular motion we have

$\theta =\omega _{o}t+\frac{1}{2}\alpha t^{2}\\\\\theta =1.69\times 0.194+05\times 5.62\times0.194^{2}\\\\\theta = 0.4336rad$

3) The tangential speed is given as

$v_{t}=\omega _{f}\times r\\\\v_{t}=2.78\times\frac{0.790}{2}=1.098m/s$

The resultant acceleration is given by

$a_{res}=\sqrt{(a_{tangential})^{2}+(a_{radial})^{2}}\\\\a_{res}=\sqrt{(\alpha r)^{2}+(\omega _{f}^{2}r)^{2}}\\\\a_{res}=3.77m/s^{2}$

5 0

3 years ago

Explain the relationship between short and long wavelengths and low and high frequency

murzikaleks [220]

Answer:

Wavelength and frequency are inversely related.

Explanation:

-Longer waves have lower frequencies.

-Shorter waves have longer frequencies.

-This simply implies that that as the length of the wavelength increases it's frequency reduces.

8 0

3 years ago

A car starts from rest and accelerates at 4 m/s^2 for 8 s, after which it continues at constant speed for 19 s. How far would it

ser-zykov [4K]

Answer:

The total distance traveled is 736 m

Solution:

According to the question:

Initial velocity, v = 0

(since, the car is starting from rest)

$acceleration, a = 4 m/s^{2}$

Time taken, t = 8 s

Now, the distance covered by it in 8 s is given by the second eqn of motion:

$d = vt + \farc{1}{2}at^{2}$

$d = 0.t + \farc{1}{2}4\times 8^{2} = 128 m$

Now, to calculate the velocity, we use eqn 1 of motion:

v' = v + at

v' = 0 + 4(8) = 32 m/s

Now, the distance traveled by the car with uniform velocity of 32 m/s for t' = 19 s:

distance, d' = v't'

$d' = 32\times 19 = 608 m$

Total distance traveled = d + d' = 128 + 608 = 736 m

4 0

3 years ago

Ok I am done waiting for an answer for 5 hours can somebody PLEASE PLEASE PLEASE help me TIMED ASSESMENT HERE!!!! PLEASE

JulsSmile [24]

Answer:

Explanation:

I'm going to assume that all the givens are in m/s. If I am correct, The orange line is speeding up. It is going from 4 m/s to 7 m/s. Its slant is from lower left to upper right. It is increasing in speed.

The green line is slowing down. It is going from 4 to 0 m/s. It's slant is from upper left to lower right.

The blue line is horizontal. It is neither slowing down or speeding up.

3 0

3 years ago

Read 2 more answers

A 300 g bird is flying along at 6.0 m/s and sees a 10 g insect heading straight towards it with a speed of 30 m/s. The bird open

Gelneren [198K]

Answer:

(a): The bird speed after swallowing the insect is V= 4.83 m/s

(b): The impulse on the bird is I= 0.3 kg m/s

(c): The force between the bird and the insect is F= 20 N

Explanation:

ma= 0.3 kg

va= 6 m/s

mb= 0.01kg

vb= 30 m/s

(ma*va - mb*vb) / (ma+mb) = V

V= 4.83 m/s (a)

I= mb * vb

I= 0.3 kg m/s (b)

F*t= I

F= I/t

F= 20 N (c)

5 0

3 years ago