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den301095 [7]
3 years ago
8

In your own words, explain Newton’s first law of motion.

Physics
2 answers:
Over [174]3 years ago
5 0
Newton's first law of motion states that. an object on the rest or motion is stay the same unless external force applied on it.
Daniel [21]3 years ago
4 0

A object at rest will stay at rest and a object in motion will stay in motion unless acted upon by a external force. Hope this helps

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A 50 W light bulb is plugged into a standard
wolverine [178]

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

energy =50x31x24=37200

=37.2kwh

1kwh =3.39

37.2kwh=3.39x37.2=126.108cent

=$1.26

8 0
2 years ago
the kinetic energy of an object of mass in moving with a velocity of 5 MS -1 is 25j what will be its kinetic energy when its vel
MAXImum [283]

Answer:

<em>When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy an object has due to its speed. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

The object has a kinetic energy of K=25 J when moving at v=5 m/s, thus the mass can be calculated by solving for m:

\displaystyle m=\frac{2K}{v^2}

\displaystyle m=\frac{2*25}{5^2}=2

m = 2 Kg

If the speed is doubled, v=10 m/s, the new kinetic energy is:

\displaystyle K=\frac{1}{2}2\cdot 10^2

K = 100 J

If the speed is tripled, v=15 m/s, the new kinetic energy is:

\displaystyle K=\frac{1}{2}2\cdot 15^2

K = 225 J

When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J

3 0
3 years ago
The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate
ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

B)

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}      ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

\theta=\frac{3.7m}{0.162m}=22.83rad

22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}

to calculate the angular speed w we can use\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}

Thus, wf=12.68rad/s

C) We can use our result in B)

\alpha=3.52\frac{rad}{s^2}

I hope this is useful for you

regards

3 0
3 years ago
Read 2 more answers
Use 3rd law to explain how a fish swims through water. Identify the force pairs and draw a diagram.
vovikov84 [41]
Well as the fish swims he pushes the water behind him which in return push him forward
5 0
3 years ago
What would it mean if neither the red or blue litmus paper changes colors?
Anna35 [415]

if the color changes, it is neutral but if it stays the same, it is an acid.

8 0
3 years ago
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