Answer:
u = 44.44 m/s
Explanation:
given,
horizontal displacement = 50 m
maximum height = 100 m
initial velocity (v₀) = ?
launching angle(θ) = ?
using formula
........(1)
.........(2)
dividing equation (2)/(1)
now using equation (2)
u = 44.44 m/s
-- If the two resistors are connected in series, then they behave like a single resistor whose resistance is (R₁ + R₂) ohms.
-- For any resistance, the potential difference (volts) across the resistance is V = (current) x (resistance) .
-- So in THIS circuit, <em>V = I x (R₁ + R₂)</em> .
Answer:
2.65m/s
Explanation:
Using the equation of motion:
v² = u²+2a∆S where
v is the final velocity
u is the initial velocity
∆S is the change in distance
a is the acceleration
Given
u = 0m/s
a = 9.8m/s²
∆S = 1.3-0.943
∆S = 0.357m
Substituting the given parameters into the formula
v² = 0²+2(9.8)(0.357)
v² = 0+6.9972
v² = 6.9972
v=√6.9972
v = 2.65m/s
Hence the velocity at which it hit the ground is 2.65m/s
Answer:
The standard quantity with which we carry out the measurement of any physical quantity of the same kind is called a unit.