Hydrocarbons. They usually burn. In fact, I can't think of one that does not.
Explanation:
This is correct!
Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.
An example is;
Na+(aq) + Cl−(aq) + Ag+(aq) + NO3−(aq) → Na+(aq) + NO3−(aq) + AgCl(s)
The ions; Na+, NO3−(aq) would be cancelled out to give;
Cl−(aq) + Ag+(aq) → AgCl(s)
The volume of nitrogen monoxide that occupy at STP is= 277 Ml
calculation
The volume is obtained using the combined gas law that is P1V1/T1= P2V2?
Where P1 = 720 MmHg
V1 = 400ml
T1= 100 +273= 373 K
At STP temperature = 273 K and pressure= 760 mm hg
therefore T2= 273 k
p2 = 760 mmhg
V2=?
make V2 the subject of the formula
V2= (T2 ×P1 ×V1)/(P2×T1)
V2 is therefore = (273k x720 mmhg x 400 ml)/(760 mmhg x373K) = 277 Ml
Answer:
C₆H₈O₆
Explanation:
The molecular formula of given compound is C₆H₈O₆. Because there are six carbon, six oxygen and eight hydrogen atom present in this compound.
The molecular weight of following compound is,
C₆H₈O₆
C = 12 amu
H = 1 amu
O = 16 amu
C₆H₈O₆ = 12×6 + 1×8 + 16×6
C₆H₈O₆ = 72 +8 + 96
C₆H₈O₆ = 176 g/mol