Answer:
Step 1;
q = w = -0.52571 kJ, ΔS = 0.876 J/K
Step 2
q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ
Explanation:
The given parameters are;
= 100 N·m
= 327 K
= 90 N·m
Step 1
For isothermal expansion, we have;
ΔU = ΔH = 0
w = n·R·T·ln(
/
) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71
w ≈<em> -0.52571</em> kJ
At state 1, q = w = -0.52571 kJ
ΔS = -n·R·ln(
/
) = -1 × 8.314 × ln(90/100) ≈ 0.876
ΔS ≈ 0.876 J/K
Step 2
q = 0 for adiabatic process
ΔU = 25×(27 - 327) = -7,500
w = ΔU = <em>-7.5 kJ</em>
ΔH = ΔU + n·R·ΔT
ΔH = -7,500 + 8.3142 × 300 = -5,005.74
ΔH = ΔU = <em>-5.00574 kJ</em>
Atomic mass of Potassium = Mass of 1 atom of Potassium = 39.1 amu
Then
Mass of 6.02 x 1023 atoms of potassium = 39.1 x 6.02 x 1023 amu
=
We already know that
1 mole = 6.02 x 1023 atoms
Also
Number of mole = mass in grams/ atomic mass
Then
Mass in gram = Number of mole x atomic mass
= (39.1 x 6.02 x 1023)/(6.02 x 1023)
= 39.1 g
The correct option among all the options that are given in the question is the third option or option "B".
Answer:
When two atomic orbitals come together to form two molecular orbitals, one molecular orbital will be lower in energy than the two separate atomic orbitals and one molecular orbital will be higher in energy than the separate atomic orbitals.
Explanation:
<em>Which of the following statements is TRUE? </em>
- <em>Electrons placed in antibonding orbitals stabilize the ion/molecule.</em> FALSE. Electrons in the antibonding orbitals destabilize the ion/molecule.
- <em>The total number of molecular orbitals formed doesn't always equal the number of atomic orbitals in the set.</em> FALSE. The total number of molecular orbitals is always equal to the number of atomic orbitals in the set.
- <em>When two atomic orbitals come together to form two molecular orbitals, one molecular orbital will be lower in energy than the two separate atomic orbitals and one molecular orbital will be higher in energy than the separate atomic orbitals.</em> TRUE. The orbital with lower energy will be the bonding orbital and the one with higher energy will be the antibonding orbital.
- <em>A bond order of 0 represents a stable chemical bond.</em> FALSE. A chemical bond is stable if the bond order is higher than zero.