Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
Answer:
On a roller coaster, energy changes from potential to kinetic and back again many times over and over the course of the ride. Kinetic energy is energy that an object has because of its motion. All moving objects possess kinetic energy, which is determined by the mass and speed of the object.
Explanation:
Answer:
A.) 355 m/s
B.) 0.71 m
C.) 500Hz
Explanation:
Given that a police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s
a.) What is the speed of the sound waves relative to you?
Since the car is moving away from the observer, the relative velocity will be:
Relative velocity = 340 + 15
Relative velocity = 355 m/s
b.) What is the wavelength of the sound waves at your location?
Using the wave speed formula
V = frequency × wavelength
Make wavelength the subject of formula.
Wavelength = Velocity / frequency
Wavelength = 355/500
Wavelength = 0.71 m
c.) What frequency do you detect?
Fo = Fs ( C + V ) / ( C + v )
Fo = Fs
That is, the frequency of the observer will be equal to the frequency of the source.
Therefore, Fo = 500Hz
