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Fofino [41]
3 years ago
7

A 900 kg car moves around a 500 m radius curve at 25.0 m/s. What is the centripetal force on

Physics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

9375 N

Explanation:

From the question,

Centripetal force (F) = mv²/r.................. Equation 1

Where m = mass of the car, v = velocity of the car, r = radius of the curve.

Given: m = 900 kg, r = 600 m, v = 25 m/s

Substitute these values into equation 1

F = (900×25²)/600

F = 9375 N.

Hence the centripetal force on the car is 9375 N

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Answer:

0.714 m

Explanation:

From the question,

v = λf......................... Equation 1

Where v = velocity of visible light, f = frequency of visible light, λ = wave length of visible light.

make λ the subject of the equation

λ = v/f.................. Equation 2

Given: f = 4.2×10⁸ Hz

Note: Light is an electromagnetic wave, and all electromagnetic waves travels with the same speed (3×10⁸ m/s)

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = 3×10⁸/4.2×10⁸

λ = 0.714 m

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Answer:

<em>work done in pumping the entire fuel is 466587 J</em>

<em></em>

Explanation:

weight of the gasoline per volume = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 2 m

height of the tractor tank above the top of the tank = 5 m

work done in pumping fuel to this height = ?

First, we find the volume of the fuel

since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>

<em>Also, we assume that the fuel completely fills the tank.</em>

volume of a cylinder = \pi r^{2}l

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volume of the cylinder = 3.142 x 1.5^{2} x 2 = 14.139 m^3

we then find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 14.139 = 93317.4 N

work done = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 93317.4 x 5 = <em>466587 J</em>

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