Answer:
The cross-sectional area of the larger piston is 800 cm².
Explanation:
Given;
mass of the automobile, m = 4000 kg
force applied on the small piston, F₁ = 500 N
area of the smaller piston, A₁ = 10 cm²
load lifted by the larger piston, F₂ = 4000 x 10 = 40,000 N
Pressure experienced by each piston is given as;

Where;
A₂ is the cross-sectional area of the larger piston

Therefore, the cross-sectional area of the larger piston is 800 cm².
Answer:0.46
Explanation:
Given
Initial height 
inclination 
Thrust
combined mass of kieran and skis 
Speed at the bottom 
From Work Energy Theorem
Work done by all the force is equal to change in kinetic Energy
------------1
distance traveled along the slope 



substitute in 1




Answer:
Resultant horizontal force = 143 N
Explanation:
Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;
Resultant horizontal force = 165 * cos 30
Resultant horizontal force = 142.89
Approximating to a whole number gives;
Resultant horizontal force = 143 N
Answer:
(a) 
(b) 
Explanation:
Given data
The angular velocity of two cylinders ω=257 rad/s
The mass of the two cylinders m=2.88 kg
The radius of small cylinder r₁=0.319 m
The radius of larger cylinder r₂=0.605 m
For Part (a)
The rotational kinetic energy of the cylinder is given by:

Where I is rotational of inertia of solid cylinder about its central axis.
So

Substitute the given values
So

For Part (b)

Substitute the given values

Answer:
Explanation:
the net force on the right left is 25 N and is directed upward
the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero
i hope this will help you