Answer:

Explanation:
Assume that the distance travelled initially is d.
In order to stop the block you need some external force which is friction.
If we use the law of energy conservation:

a)
Looking at the formula you can see that the mass doesn't affect the distance travelled, as lng as the initial velocity is constant (Which indicates that the force must be higher to push the block to the same speed) therefore the distance is the same.
b) If the velocity is doubled, then the distance travelled is multiplied by 4, because the distance deppends on the square of the velocity.
The area of this triangle can be calculated using herons formula since th three sides are given. It is expressed as:
A=sqrt( s(s-a)(s-b)(s-c))
where s is equal to a+b+c / 2
s=15 +20 +25 /2=30
A=sqrt( 30(30-15)(30-20)(30-25))
A= 150 cm^3
Answer:
The velocity of the acorn just before it reaches the ground is 19 m/s
The kinetic energy when hitting the ground is 3.1 J
Explanation:
Given;
mass of the acorn, m = 0.017 kg
height of fall, h = 18.5 m
Apply the law of conservation of mechanical energy;
mgh = ¹/₂mv²
gh = ¹/₂v²
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 18.5)
v = 19 m/s
Thus, the velocity of the acorn just before it reaches the ground is 19 m/s
Now, determine the kinetic energy when hitting the ground;
K.E = ¹/₂mv²
K.E = ¹/₂(0.017)(19)²
K.E = 3.09 J
K.E = 3.1 J
Therefore, the kinetic energy when hitting the ground is 3.1 J
Answer:
8 hp
Explanation:
Power = work / time
P = W/t
Work = force × distance
W = Fd
Substituting:
P = Fd/t
P = Fv
Given that F = 300 N and v = 20 m/s:
P = (300 N) (20 m/s)
P = 6000 W
P = 6 kW
Converting to horse power:
6 kW × (1 hp / ¾ kW) = 8 hp