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Advocard [28]
4 years ago
11

If the masses of objects increase and their distance from each other remains the same, then the force of gravity between the two

objects
A) decreases.
B) increases.
C) remains the same.
D) increases then decreases.
Physics
2 answers:
solniwko [45]4 years ago
8 0

Answer:

The answer is B. Increases.

Explanation:

The force of gravity expressed in a formula is equal to F = G\frac{m1m2}{d^{2} }

In which:

(F) equals the force of attraction

(G) is equal to the universal gravitation constant

(M1) represents the mass of body number 1

(M2) represents the mass of body number 2

(D) represents the distance between the two bodies

So as the masses are in the numerator, if they are increased the fraction in the same way will increase. For this reason if the masses of these bodies increases the force of gravity will also increase.

jonny [76]4 years ago
5 0
B. Increases coz Gravitational force is directly proportional to product of their masses. i. e if m increases, gravitational force increases.
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It is elastic energy
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4 years ago
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A block pushed along the floor with velocity V0 slides a distance d after the pushing force is removed. a) if the mass of the bl
KengaRu [80]

Answer:

a) \ d_2=d_1\\b) \ d_2=4d_1

Explanation:

Assume that the distance travelled initially is d.

In order to stop the block you need some external force which is friction.

If we use the law of energy conservation:

E_i=E_f\\\frac{mv^2}{2}= E_{Friction}\\E_{Friction}=F_{Friction}*d\\F_{Friction}= \mu_kmg\\\frac{mv^2}{2}= \mu_kmgd\\ d=\frac{v^2}{2\mu_kg}

a)

Looking at the formula you can see that the mass doesn't affect the distance travelled, as lng as the initial velocity is constant (Which indicates that the force must be higher to push the block to the same speed) therefore the distance is the same.

b) If the velocity is doubled, then the distance travelled is multiplied by 4, because the distance deppends on the square of the velocity.

6 0
4 years ago
find the area of a right triangle with sides 15.0 cm, 20.0 cm, and 25.0 cm. express your answer with the correct number of signi
pickupchik [31]
The area of this triangle can be calculated using herons formula since th three sides are given. It is expressed as:

A=sqrt( s(s-a)(s-b)(s-c))

where s is equal to a+b+c / 2

s=15 +20 +25 /2=30
A=sqrt( 30(30-15)(30-20)(30-25))
A= 150 cm^3
4 0
3 years ago
A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground. Calculate the velocity of the acorn
sdas [7]

Answer:

The velocity of the acorn just before it reaches the ground is 19 m/s

The kinetic energy when hitting the ground is 3.1 J

Explanation:

Given;

mass of the acorn, m = 0.017 kg

height of fall, h = 18.5 m

Apply the law of conservation of mechanical energy;

mgh = ¹/₂mv²

gh = ¹/₂v²

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 18.5)

v = 19 m/s

Thus, the velocity of the acorn just before it reaches the ground is 19 m/s

Now, determine the kinetic energy when hitting the ground;

K.E = ¹/₂mv²

K.E = ¹/₂(0.017)(19)²

K.E = 3.09 J

K.E = 3.1 J

Therefore, the kinetic energy when hitting the ground is 3.1 J

5 0
4 years ago
A car was traveling at a constant speed of 20m/s overcomes a constant frictional resistant of 300newton.. What is the horse powe
nadezda [96]

Answer:

8 hp

Explanation:

Power = work / time

P = W/t

Work = force × distance

W = Fd

Substituting:

P = Fd/t

P = Fv

Given that F = 300 N and v = 20 m/s:

P = (300 N) (20 m/s)

P = 6000 W

P = 6 kW

Converting to horse power:

6 kW × (1 hp / ¾ kW) = 8 hp

8 0
4 years ago
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