Because the move through water
The process of digestion breaks down proteins into smaller molecules that are used to rebuild other proteins. During digestion, proteins undergo chemical changes.
<u>Option: D</u>
<u>Explanation:</u>
Proteins are broken down into amino acids considered the foundational element. When issued, these tiny molecules can then be consumed into the bloodstream via the gut wall. An enzyme is a protein which can regulate biochemical response rate. An enzyme integrates a water molecule around the bond in enzymatic hydrolysis processes which allows it to split.
The bonds which hold together the amino acids are recognized as peptide bonds. A hydrolysis process comparable to that included in splitting up carbohydrates is required to break the peptide bonds within a protein. Enzymes identified as proteases are required for the protein to disintegrate.
If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m
Given the data in the question;
- Length of the massless beam;
![L = 4.00m](https://tex.z-dn.net/?f=L%20%3D%204.00m)
- Distance of support from the left end;
![x = 3.00m](https://tex.z-dn.net/?f=x%20%3D%203.00m)
- First mass;
![m1 = 31.3 kg](https://tex.z-dn.net/?f=m1%20%3D%2031.3%20kg)
- Distance of beam from the left end( m₁ is attached to );
![x_1 = ?](https://tex.z-dn.net/?f=x_1%20%3D%20%3F)
- Second mass;
![m_2 = 61.7 kg](https://tex.z-dn.net/?f=m_2%20%3D%2061.7%20kg)
- Distance of beam from the right of the support( m₂ is attached to );
![x_1 = 0.273m](https://tex.z-dn.net/?f=x_1%20%3D%200.273m)
Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.
Hence, ![m_1g( x-x_1) = m_2gx_2](https://tex.z-dn.net/?f=m_1g%28%20x-x_1%29%20%3D%20m_2gx_2)
we divide both sides by ![g](https://tex.z-dn.net/?f=g)
![m_1( x-x_1) = m_2x_2](https://tex.z-dn.net/?f=m_1%28%20x-x_1%29%20%3D%20m_2x_2)
Next, we make
, the subject of the formula
![x_1 = x - [ \frac{m_2x_2}{m_1} ]](https://tex.z-dn.net/?f=x_1%20%3D%20x%20-%20%5B%20%5Cfrac%7Bm_2x_2%7D%7Bm_1%7D%20%5D)
We substitute in our given values
![x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]](https://tex.z-dn.net/?f=x_1%20%3D%203.00m%20-%20%5B%20%5Cfrac%7B61.7kg%5C%20%2A%20%5C%200.273m%7D%7B31.3kg%7D%20%5D)
![x_1 = 3.00m - 0.538m](https://tex.z-dn.net/?f=x_1%20%3D%203.00m%20-%200.538m)
![x_1 = 2.46m](https://tex.z-dn.net/?f=x_1%20%3D%202.46m)
Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m
Learn more; brainly.com/question/3882839
12m S=0m E, -12m N
15m 55d E of N = 15 sin 55, 15 cos 55 N
Sum= (15sin55)m E, (-12 + 15 cos 55)m N
<em>Answer:</em>
<h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>True</em></h3>
- <em>Because </em><em>Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water. ... Gravity pulls denser air and water downward, forcing less dense air and water to move upward.</em>
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