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2 years ago

Things you can do with an environmental engineering major and a broadcasting minor?

Physics

1 answer:

Vika [28.1K]2 years ago

7 0

Answer:

With an Environmental Engineering and a broadcasting minor

You can work as an On Air personality that host programs that provide your audience with documentaries about the environments and project carried out by Environmental Engineer

and also you can work as a journalist that explore the world making research that will preserve the environment and leveraging the media as a broadcaster to provide this research findings as a video for you audience

Explanation:

In order to get a better understanding let define some terms

Environmental Engineer :

Environmental engineers resolve and help prevent environmental problems. They work in many areas, including air pollution control, industrial hygiene, toxic materials control, and land management. The duties of an environmental engineer range from planning and designing an effective waste treatment plant to studying the effects of acid rain on a particular area. An environmental engineer is sometimes required to work outdoors, though most of her work is done in a laboratory or office setting. Career opportunities for environmental engineers exist in consulting, research, corporate, and government positions.

Broadcasting:

Broadcasting is the distribution of audio or video content to a dispersed audience via any electronic mass communications medium, but typically one using the electromagnetic spectrum (radio waves), in a one-to-many model.

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_______ are pictures of relationships.

S_A_V [24]

Answer:

Graphs

Explanation:

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2 years ago

Read 2 more answers

A baseball of mass 300-g is hit at a velocity of 40 m/s. If the ball is caught by the third baseman and the ball penetrates 2.0

OlgaM077 [116]

The force is -12,000 N

Explanation:

First of all, we calculate the acceleration of the ball, by using the following suvat equation:

$v^2-u^2=2as$

where:

v = 0 is the final velocity of the baseball (it comes to rest)

u = 40 m/s is the initial velocity

a is the acceleration

s = 2.0 cm = 0.02 m is the displacement of the ball

Solving for a,

$a=\frac{v^2-u^2}{2s}=\frac{0-40^2}{2(0.02)}=-40,000 m/s^2$

Now we can calculate the average force exerted on the ball, by using Newton's second law:

$F=ma$

where

m = 300 g = 0.3 kg is the mass of the ball

$a=-40,000 m/s^2$ is the acceleration

Substituting,

$F=(0.3)(-40,000)=-12,000 N$

where the negative sign indicates that the direction of the force is opposite to the direction of motion of the ball.

Learn more about forces:

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8 0

2 years ago

Suppose that a person riding on the top of a freight car shines a searchlight beam in the direction in which the train is travel

Snezhnost [94]

Answer:

same

Explanation:

Acc. to Einstien's postulate of special theory of

Relativity , Velocity of the light beam is same in all frames of references

(a) If the freight car is at rest

The frame we can assumed as Non - inertial frame of reference s

In the inertial frame of reference , velocity of the light beam has its own value as : 3 x 10^8 m/s

(b) If the freight car is moving , the frame we can assumed as Non -inertial frame of reference

In thus case also , The velocity of the light beam will also have the same value as ; 3 x 108 m/s

6 0

3 years ago

En la figura los émbolos son de masa despreciable y están en reposo, como se ve en la figura, siendo M=300 kg. Determine: a) la

Leni [432]

The image mentioned is in the attachment

Answer: a) P = 2450 Pa;

b) P = 2940 Pa;

c) F = 4.9 N

Explanation:

a) Pressure is a force applied to a surface of an object or fluid per unit area.

The image shows a block applying pressure on the large side of the piston. The force applied is due to gravitation, so:

P = $\frac{F}{A}$

P = $\frac{m.g}{A}$

P = $\frac{300.9.8}{1.2}$

P = 2450 Pa

The pressure generated by the block is P = 2450 Pa.

b) A static liquid can also exert pressure and can be calculated as:

$P_{staticfluid} =$ ρ.g.h

where

ρ is the density of the fluid

h is the depth of the fluid

g is acceleration of gravity

$P_{staticfluid} =$ 600.9.8.0.5

$P_{staticfluid} =$ 2940 Pa

The pressure in the fluid at 50 cm deep is $P_{staticfluid} =$ 2940 Pa.

c) For the system to be in equilibrium both pressures, pressure on the left side and pressure on the right side, have to be the same:

$P_{s} = P_{b}$

$\frac{F}{A_s}$ = $\frac{F_b}{A_b}$

F = $\frac{F_b}{A_b}.A_s$

Adjusting the units, $A_{s}$ = 0.002 m².

F = $\frac{300.9.8.0.002}{1.2}$

F = 4.9 N

The force necessary to be equilibrium is F = 4.9 N.

4 0

2 years ago

Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ

Oksi-84 [34.3K]

Answer:

The number is $Z = 216 \ fringes$

Explanation:

From the question we are told that

The wavelength is $\lambda = 520 \ nm = 520 *10^{-9} \ m$

The length of the glass plates is $y = 21.1cm = 0.211 \ m$

The distance between the plates (radius of wire ) = $d = 0.028 mm = 2.8 *10^{-5} \ m$

Generally the condition for constructive interference in a film is mathematically represented as

$2 * t = [m + \frac{1}{2} ]\lambda$

Where t is the thickness of the separation between the glass i.e

t = 0 at the edge where the glasses are touching each other and

t = 2d at the edge where the glasses are separated by the wire

m is the order of the fringe it starts from 0, 1 , 2 ...

$2 * 2 * d = [m + \frac{1}{2} ] 520 *10^{-9}$

=> $2 * 2 * (2.8 *10^{-5}) = [m + \frac{1}{2} ] 520 *10^{-9}$

$m = 215$

given that we start counting m from zero

it means that the number of bright fringes that would appear is

$Z = m + 1$

=> $Z = 215 +1$

=> $Z = 216 \ fringes$

3 0

2 years ago