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telo118 [61]
3 years ago
6

Which is true about the pH values of a 1.0 M solution of HCl (a strong acid) and a 1.0 M solution of HC2H3O2 (a weak acid)?

Chemistry
1 answer:
Neko [114]3 years ago
4 0

Answer:

C. pH values are different because the HC_2H_3O_2 solution partially ionizes and the HCl solution ionizes 100 percent.

Explanation:

Strong acids are the acids which completely ionizes in the solution while weak acids are the acids which ionizes partially in the solution. They exists in equilibrium in the solution with their respective ions.

Thus, strong acids furnish greater concentration of protons as compared to weak acid when same concentration of both types are taken.

<u>Also, pH is the negative of the logarithm  of the hydrogen ions. Thus, hydrogen ion concentration for both acids are different and thus pH will be different.</u>

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3 years ago
Consider the following three-step reaction pathway.
Alenkinab [10]

Answer:

NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2

Explanation:

The intermediates are the products of all the steps of the reaction pathway, with the exception of the last one. So the intermediates will be:

  • N2O2 from the first step
  • N2O from the second step

The list from reactant to final product:

NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2

<em>Note: the water is considered a by-product, given that is not the product of interest in this steps.</em>

7 0
3 years ago
Covalent compounds occur------
irga5000 [103]

Answer:

Only between nonmetals

Explanation:

  • Covalent compounds are compounds that are formed as a result of covalent bonding between nonmetal atoms.
  • Covalent compounds occur only between non metals, where atoms of the nonmetals involved join to form a covalent bond as a result of sharing of electrons.
  • <u><em>Electrons shared during the formation of covalent bond, may be from one atom involved or each atom contributing equally to the bond formation.</em></u>
  • An example of covalent compounds include, phosphorus (v) oxide, methane, water, CO2,etc.
4 0
3 years ago
A mixture of XO2 (P = 3.00 atm) and O2 (P = 1.00 atm) is placed in a container. This elementary reaction takes place at 27 °C: 2
sukhopar [10]

Answer:

a) \triangle G^{0} = 7.31 kJ/mol

b) K_{-1} = 0.0594 m^{-1} s^{-1}

Explanation:

Equation of reaction:

                                     2 XO_{2} (g) + O_{2} (g) \rightleftharpoons 2XO_{3} (g)

Initial pressure                  3              1              0

Pressure change             2P           1P             2P

Total pressure = (3-2P) + (1-P) + (2P)

Total Pressure = 3.75 atm

(3-2P) + (1-P) + (2P) = 3.75

4 - P = 3.75

P = 4 - 3.75

P = 0.25 atm

Let us calculate the pressure of each of the components of the reaction:

Pressure of XO2 = 3 - 2P = 3 - 2(0.25)

Pressure of XO2 =2.5 atm

Pressure of O2 = 1 - P = 1 -0.25

Pressure of O2 = 0.75 atm

Pressure of XO3 = 2P = 2 * 0.25

Pressure of XO3 = 0.5 atm

From the reaction, equilibrium constant can be calculated using the formula:

K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }

K_{p} = \frac{0.5^2}{2.5^2 *0.75} \\K_{p} = 0.0533 = K_{eq}

Standard free energy:

\triangle G^{0} = - RT ln k_{eq} \\\triangle G^{0} = -(0.008314*300* ln0.0533)\\\triangle G^{0} = 7.31 kJ/mol

b) value of k−1 at 27 °C, i.e. 300K

K_{1} = 7.8 * 10^{-2} m^{-2} s^{-1}

K_{c} = K_{p}RT\\K_{c} = 0.0533* 0.0821 * 300\\K_{c} = 1.313 m^{-1}

K_{-1} = \frac{K_{1} }{K_{c} } \\K_{-1} = \frac{7.8 * 10^{-2}  }{1.313 }\\K_{-1} = 0.0594 m^{-1} s^{-1}

6 0
3 years ago
The Oxidation number of iron in the Complexion [Fe(CN) 6]³^- is what?​
LUCKY_DIMON [66]

+3

Hence, the magnetic behaviour of the complex is paramagnetic. The oxidation number of the central metal atom: The oxidation number of the metal iron is +3.

4 0
2 years ago
Read 2 more answers
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