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erma4kov [3.2K]
3 years ago
15

When 155 mL of water at 26 C is mixed with 75 mL of water at 85 C, what is the final temperature? (assume that no heat is releas

ed to the surroundings; d of water = 1.00g/mL.)
Chemistry
1 answer:
Ket [755]3 years ago
6 0
Depends if it desolved with the water or not

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4. Refer the table given below to answer the questions fon Electronic configuration Element Atomic number 11 R 19 2,8,1 2,8,8, 1
denpristay [2]

Answer:

The electronic configuration of the element with Atomic number 19 is 2,8,8,1. The element is potassium. It is an alkali metal with one valence electron.

7 0
3 years ago
Name some acids and in what and how we used them
Ne4ueva [31]

Answer:

Acid Uses

Organic acids

Citric acid As a preservative for food As a flavouring agent

Ascorbic acid (also called vitamin C) In the treatment of bone marrow and scurvy diseases

Acetic acid Added to pickles to make them sour

Explanation:

7 0
2 years ago
Why is not used at nuclear plant as a soverce for electrical energy
nikitadnepr [17]
The biggest reason is radioactive wastes. Nuclear power generated radioactive wastes like Uranimum, plutonium and amercium that inhibits gene expression and causes cancer to the environment. Nuclear plants use to release these wastes into the oceans, and it causes fishes to exhibit gender change, 3 eyes, 2 tails etc. The impact on human shows signs of serious blood, liver and lung cancers. 

There are currently no way to get rid of these wastes as they take hundred thousands of years to decompose. 

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7 0
2 years ago
What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?
Lubov Fominskaja [6]

Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})

Hence, the probability of finding the particle in the  one-dimensional box is:

P = \int_{x_{1}}^{x_{2}} \psi^{2} dx

P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx

P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]

P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})    

Solving for n=4:

P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})    

P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})    

P = \frac{1}{8}

I hope it helps you!

7 0
3 years ago
PLEASE HELP, CHEMISTRY!!! 20 POINTS!!!
mart [117]

the answer is in the picture

6 0
3 years ago
Read 2 more answers
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