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ozzi
2 years ago
9

Could somebody please look at the questions in the image and answer them for me? Please provide a detailed explanation with the

answer. Thank you in advance!​

Physics
1 answer:
anzhelika [568]2 years ago
4 0

Answer:

a) 3 N

b) 48 N

c) 24 N

d) 48 N

e) 6 N

Explanation:

Newton's law of gravitation states that the force between two masses is:

F = G m₁ m₂ / r²

At the original mass and distance, the force is 12 N.

12 = G m₁ m₂ / r²

a) If r is doubled:

F = G m₁ m₂ / (2r)²

F = G m₁ m₂ / (4r²)

F = 1/4 G m₁ m₂ / r²

F = 1/4 (12)

F = 3 N

b) If r is halved:

F = G m₁ m₂ / (r/2)²

F = G m₁ m₂ / (r²/4)

F = 4 G m₁ m₂ / r²

F = 4 (12)

F = 48 N

c) If one of the masses is doubled:

F = G (2 m₁) m₂ / r²

F = 2 G m₁ m₂ / r²

F = 2 (12)

F = 24 N

d) If both masses are doubled:

F = G (2 m₁) (2 m₂) / r²

F = 4 G m₁ m₂ / r²

F = 4 (12)

F = 48 N

e) If one of the masses is doubled and the distance is doubled:

F = G (2 m₁) m₂ / (2r)²

F = G (2 m₁) m₂ / (4r²)

F = 1/2 G m₁ m₂ / r²

F = 1/2 (12)

F = 6 N

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4 0
3 years ago
Consider an insulating sphere of radius 6 cm surrounded by a conducting sphere of inner radius 18 cm and outer radius 26 cm. Fur
dimulka [17.4K]

Answer:

-1.7908787542\times 10^{-9}\ C

3.4260289211\times 10^{-9}\ C

1.7908787542\times 10^{-9}\ C

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Explanation:

r = Radius

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Electric field is given by

E=-\dfrac{kq}{r^2}\\\Rightarrow q=-\dfrac{Er^2}{k}\\\Rightarrow q=-\dfrac{1610\times 0.1^2}{8.99\times 10^9}\\\Rightarrow q=-1.7908787542\times 10^{-9}\ C

The charge is -1.7908787542\times 10^{-9}\ C

Q+q=\dfrac{Er^2}{k}\\\Rightarrow Q=\dfrac{Er^2}{k}-q\\\Rightarrow Q=\dfrac{120\times 0.35^2}{8.99\times 10^9}-(-1.7908787542\times 10^{-9})\\\Rightarrow Q=3.4260289211\times 10^{-9}\ C

The charge is 3.4260289211\times 10^{-9}\ C

The charge inside will have the polarity changed

q=+1.7908787542\times 10^{-9}\ C

Outside the charge will be

3.4260289211\times 10^{-9}-1.7908787542\times 10^{-9}\\ =1.6351501669\times 10^{-9}\ C

3 0
3 years ago
The AC voltage source is connected to an inductor and a resistor in series. If the frequency of the source is increased the curr
DaniilM [7]

Answer:

If the frequency of the source is increased the current in the circuit will decrease.

Explanation:

The current through the circuit is given as;

I = \frac{V}{Z}

Where;

V is the voltage in the AC circuit

Z is the impedance

Z = \sqrt{R^2 + X_L^2}

Where;

R is the resistance

X_L is the inductive reactance

X_L = ωL = 2πfL

where;

L is the inductance

f is the frequency of the source

Finally, the current in the circuit is given as;

I = \frac{V}{\sqrt{R^2 + (2\pi fL)^2} }

From the equation above, an increase in frequency (f) will cause a decrease in current (I).

Therefore, If the frequency of the source is increased the current in the circuit will decrease.

5 0
3 years ago
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student
puteri [66]

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

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We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

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Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

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2 years ago
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Answer:

Explanation:

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2 years ago
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