A 5000-kg freight car crashes into a 10,000-kg freight car at rest. They couple upon collision and move with a speed of 2 m/s. W
1 answer:
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Answer:
50.97 m
Explanation:
m = Mass of truck
= Coefficient of static friction = 0.4
v = Final velocity = 0
u = Initial velocity = 72 km/h =
s = Displacement
Force applied
Frictional force
Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide
Since the obect will be decelerating the acceleration will be
From the kinematic equations we have
So, the minimum distance at which the car will stop without making the load shift is 50.97 m.
Answer:
The radius of the wetter area expands at a rate of milimeters per second when radius is 150 milimeters.
Explanation:
From Geometry we remember that area of a circle is described by this expression:
(Eq. 1)
Where:
- Radius of the circle, measured in milimeters.
- Area of the circle, measured in square milimeters.
Then, the rate of change of the area in time is derived by concept of rate of change, that is:
(Eq. 2)
Where:
- Rate of change of radius in time, measured in milimeters per second.
- Rate of change of area in time, measured in square milimeters per second.
Now the rate of change of radius in time is cleared within equation above:
If we know that and
, then the rate of change of radius in time is:
The radius of the wetter area expands at a rate of milimeters per second when radius is 150 milimeters.