What happens when light passes from air into water?

When a 7.00 g7.00 g sample of KBrKBr is dissolved in water in a calorimeter that has a total heat capacity of 2.72 kJ⋅K−1,2.72 k

algol13

Answer : The molar heat of solution of KBr is 19.9 kJ/mol

Explanation :

Mass of KBr = 7.00 g

Molar mass of KBr = 119 g/mole

Heat capacity = 2.72 kJ/K

Change in temperature = 0.430 K

First we have to calculate the moles of KBr.

$\text{ Moles of }KBr=\frac{\text{ Mass of }KBr}{\text{ Molar mass of }KBr}=\frac{7.00g}{119g/mole}=0.0588moles$

Now we have to calculate the heat of the reaction.

$q=c\times \Delta T$

where,

q = amount of heat = ?

$c$ = heat capacity = $2.72kJ/K$

$\Delta T$ = change in temperature = 0.430 K

Now put all the given values in the above formula, we get:

$q=2.72kJ/K\times 0.430K$

$q=1.17kJ$

Now we have to calculate the molar heat of solution of KBr.

$\text{Molar heat of solution of }KBr=\frac{q}{n}$

where,

n = number of moles of KBr

$\text{Molar heat of solution of }KBr=\frac{1.17kJ}{0.0588moles}=19.9kJ/mol$

Therefore, the molar heat of solution of KBr is 19.9 kJ/mol

4 0

4 years ago

Describe the role of the ocean in the water cycle?

Ne4ueva [31]

Answer:

Don't get me wrong the seas are, by distant, the biggest store of water on soil, over 96% of all of Earth's water exists within the seas. Not as it were do the seas give dissipated water to the water cycle, they moreover permit water to move all around the globe as sea streams. I mean, that's all i know man, give me a break.

Explanation:

5 0

3 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST!

stira [4]

The correct answer is option a, that is, they produce ions when dissolved in water.

The acids and bases refer to the chemical components, which reacts with water. The molecules of acids dissociate to give hydrogen ions to water, while the bases dissociate to provide hydroxide ions to the water, or that takes hydrogen ions from water and leave the hydroxide ions behind.

7 0

3 years ago

Read 2 more answers

A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na

s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f: after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

$Normality=molarity \times n-factor$

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point: $N_1V_1=N_2V_2$

Before equivalence point : $N_1V_1>N_2V_2$

After the equivalence point: $N_1V_1$

$N_1V_1=100\times1=100$

case a: 5.00 mL of 1.00 M NaOH

$N_2V_2=5\times1=5$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

$N_2V_2=100\times1=100$

$N_1V_1=N_2V_2$ hence it is equivalence point

case c: 10.0 mL of 1.00 M NaOH

$N_2V_2=10\times1=10$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

$N_2V_2=150\times1=150$

$N_1V_1$ hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

$N_2V_2=50\times1=50$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

$N_2V_2=200\times1=200$

$N_1V_1$ hence it is after the eqivalence point

7 0

3 years ago

Which statements are true? Check all that apply. Check all that apply. The higher the temperature, the more soluble most ionic s

snow_lady [41]

Answer:

The higher the temperature, the more soluble most ionic solids are in water

As you cool a saturated solution from high temperature to low temperature, solids start to crystallize out of solution if you achieve a supersaturated solution.

If you raise the temperature of a saturated solution, you can (usually) add more solute and make the solution even more concentrated.

Explanation:

For many ionic solids, solubility in water increases with increase in the temperature of the solution.

This implies that increasing the temperature allow more solute to dissolve in the solvent, supersaturation may be achieved by so doing. As the solution is cooled, the solid crystalizes out of solution hence the answers above.

8 0

3 years ago