Answer:
The answer is Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
Explanation:
The reaction is first order with respect to Ce^4+ and first order with respect to Mn^2+ below.
Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
The rate calculation,
Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
This is the catalyzed reaction.
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The state in which the forward reaction rate and the reverse reaction rate are equal. Th concentration of chemicals don’t change
<h3><u>Answer;</u></h3>
<u> = 1319.45 Joules </u>
<h3><u>Explanation;</u></h3>
Kinetic energy is the energy possessed by a body in motion;
It is given by the formula; 1/2mv², where m is the mass of the body and v is the velocity.
mass = 89.5 kg and v =5.43 m/s
Therefore;
Kinetic energy = 1/2 × 89.5 × 5.43 ²
<u> = 1319.45 Joules </u>
Answer:
30 g
Explanation:
<em>For CaCl₂</em>
3CaCl₂ + 2Na₃PO₄ ⟶ Ca₃(PO₄)₂ + 6NaCl
Moles of CaCl₂ = <em>c</em>×<em>V</em> = 5.0 × 10⁻² × 2.0 = 0.100 mol
Moles of Na₃PO₄ = 0.100 × 2/3 = 0.0667 mol
Mass of Na₃PO₄ = 0.0667 × 163.94 = 10.9 g
———————————————————
<em>For Mg(NO₃)₂
</em>
3Mg(NO₃)₂ + 2Na₃PO₄ ⟶ Mg₃(PO₄)₂ + 6NaCl
Moles of Mg(NO₃)₃ = <em>c</em>×<em>V</em> = 8.5 × 10⁻² × 2.0 = 0.170 mol
Moles of Na₃PO₄ = 0.170 × 2/3 = 0.113 mol
Mass of Na₃PO₄ = 0.113 × 163.94 = 1 g
—————————————————
Total mass of Na₃PO₄ = 10.9 + 18.6 = 29.5 g
To two significant figures, mass = 30 g
