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3 years ago

2. What is the mass of 16.3 L of helium gas?

Chemistry

2 answers:

sashaice [31]3 years ago

7 0

Answer:

mass = 2.91 grams

Explanation:

Base on Avogadro's law, At standard temperature and pressure the molar volume is the same for an ideal gas. Base on this practical principle the molar volume of gases is 22.4 dm³ per mol.

Since the molar mass of 1 mol of helium is 4.002602, this simply means the molar volume which is 22.4 dm³ = 4.002602.

Convert dm³ to liter ,

1 dm³(cubic decimeter) = 1 liter

22.4 dm³ = 22.4 liter

Therefore,

if 22.4 = 4.002602

16. 3 = mass of the helium gas

cross multiply

mass = 16.3 × 4.002602/22.4

mass = 65.2424126/22.4

mass = 2.91260770536 grams

mass = 2.91 grams

lilavasa [31]3 years ago

3 0

(16.3 L) / (22.414 L/mol) x (4.0026 g He/mol) = 2.91 g

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3 years ago

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Answer:

Explanation has been given below.

Explanation:

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3 years ago

The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the limiti

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Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

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C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

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Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

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$The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%$

The percentage yield = 83.77%.

7 0

3 years ago