Question

What volume, in milliliters, of a 0.140 M solution of KCl contains 2.65 g of the compound?

Answer 1

Answer:

Calculate moles KCl: 2.55 g / 74.55 g/mol = 0.0342 moles KCl

Volume KCl = 0.0342 mol X (1 L/0.150 mol) = 0.228 L X 1000 mL/L = 228 mL

Explanation: