Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

$ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g$

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

$PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)$

Hence, we can see that the scale will read 112 grams.

Have a nice day!

7 0

4 years ago

At a certain temperature, the K p Kp for the decomposition of H 2 S H2S is 0.746 0.746 . H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g )

Ivanshal [37]

Answer: The total pressure of container at equilibrium is 0.431 bar

Explanation:

We are given:

Pressure of hydrogen sulfide = 0.240 bar

The given chemical equation follows:

$H_2S(g)\rightleftharpoons H_2(g)+S(g)$

Initial: 0.240

At eqllm: 0.240-x x x

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{H_2}\times p_S}{p_{H_2S}}$

We are given:

$K_p=0.746$

Putting values in above expression, we get:

$0.746=\frac{x\times x}{0.240-x}\\\\x=0.191,-0.940$

Neglecting the negative value of 'x' because pressure cannot be negative.

So, the equilibrium pressure of hydrogen gas = x = 0.191 bar

The equilibrium pressure of sulfur gas = x = 0.191 bar

The equilibrium pressure of hydrogen sulfide gas = (0.240 - x) = (0.240 - 0.191) = 0.049 bar

Total pressure of the container at equilibrium = $p_{H_2}+p_{S}+p_{H_2S}$

Total pressure of the container at equilibrium = 0.191 + 0.191 + 0.049 = 0.431 bar

Hence, the total pressure of container at equilibrium is 0.431 bar

6 0

4 years ago

Can someone help me please

dsp73

I think silicon(Si) is the best example of semiconductors

6 0

3 years ago