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elena-s [515]
3 years ago
8

Explain in molecular terms what would have to be done to a plant oil to transform it to a trans fat.

Chemistry
1 answer:
Rainbow [258]3 years ago
3 0
Plant oil is differnent from trans fat, but plant oil is usually used for medical stuff.
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Please help both these answers use the graph . I will mark brainly !!
____ [38]

1 is 4

2 is d

hope it helps


3 0
4 years ago
How do you know something is there if you can't see it? *
lesantik [10]

We can only see things if they give off light but be we use other senses to gather information about things we cannot see.

8 0
3 years ago
What is the halogen in period 5?? it has six letters
Misha Larkins [42]
Simple,

take a look at your periodic table, if you have it labeled look at the Halogen

Group, it includes: Flourine, Chlorine, Bromine, Iodine, and Astatine.

Now, a period on the periodic table is read from left to right, and goes

down the rows of the periodic table.

Go to Period 5, go all the way to the Halogens, what is there? 

Iodine.

Thus, your answer.
8 0
3 years ago
An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 151.0 g of water was found to have a
Tasya [4]

ccccccccccccccccccccccccccccccccccc

8 0
4 years ago
The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
garri49 [273]

Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater (m_{sw}), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

m_{sw} = \rho_{sw}\cdot V_{sw}

Where:

\rho_{sw} - Density of seawater, measured in grams per liters.

V_{sw} - Volume of seawater, measured in liters.

If V_{sw} = 1.5\times 10^{21}\,L and \rho_{sw} = 1030\,\frac{g}{L}, then:

m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)

m_{sw} = 1.545\times 10^{24}\,g

The total mass of sodium chloride is determined by the following ratio:

r = \frac{m_{NaCl}}{m_{sw}}

m_{NaCl} = r\cdot m_{sw}

Given that m_{sw} = 1.545\times 10^{24}\,g and r = 0.035, the total mass of sodium chloride in all the seawater in the world is:

m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)

m_{NaCl} = 5.408\times 10^{22}\,g

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

8 0
4 years ago
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