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UNO [17]
2 years ago
6

G to ml,density=3.291 g/ml

Physics
1 answer:
olya-2409 [2.1K]2 years ago
7 0
The density value 3.291 g/ml (gram / milliliter) in words is "three point two nine one g/ml (gram / milliliter)".
=)
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during conversion water to ice,forces of attraction between molecules. OPTIONS:1.)Decreases 2.)Increases 3.)Does not change 4.)C
In-s [12.5K]

because water is loosely packed but when it is cold it becomes closely packed in order to form ice and thus the force attraction between them also increase.

4 0
3 years ago
What was your electric potential relative to a metal pipe if a spark jumped 1.1 cm through dry air from your finger to the pipe?
romanna [79]
The electric field is given by volts/distance: E= \frac{V}{d}.  The breakdown voltage of dry air is about 3x10^6V/m.  So solving for V we get
V=Ed
or V=(3e6V/m)(0.011m)=33,000V
6 0
3 years ago
Read 2 more answers
H E L P ! ! !
madam [21]
The Correct answer to number 1 is A or D

The correct answer to number 2 is C because transmission meaning is to travel.

PS. I think number 1 is D
3 0
3 years ago
The Olympic record for a marathon is 2.00 hour 9.00 minute 21.0 seconds if the average speed of the runner achieving this record
iren2701 [21]
(2.00 hours) x (3,600 seconds/hour)  =  7,200 seconds

(9.00 minutes) x (60 seconds/minute)  =  540 seconds

The record time = (7,200 + 540 + 21) = 7,761 seconds

Distance  =  (speed) x (time)

                 = (5.436 m/s) x (7,761 sec)  =<span>  42,188.8 meters
________________________________________________
</span>
The official length of the marathon run is  42,195 meters.
If we divide that by the record time in the question, we get

                       5.4368... m/s .

Rounded to the nearest thousandth, that's  5.437 m/s.

If the question had given the speed as  5.437  instead of  5.436 ,
then we would have calculated the distance to be 

            (5.437 m/s) x (7,761 sec)  =<span>  42,196.6 meters,

4.6 meters closer to the official distance than the answer we did get.
</span>
3 0
2 years ago
What is the threshold frequency ν0 of cesium? note that 1 ev (electron volt)=1.60×10−19 j. express your answer numerically in he
andreyandreev [35.5K]

The threshold frequency fo of Cesium is 4.83 × 10¹⁴ Hz

<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

\large {\boxed {E = h \times f}}

<em>E = Energi of A Photon ( Joule )</em>

<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>

<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}

\large {\boxed {E = qV + \Phi}}

<em>E = Energi of A Photon ( Joule )</em>

<em>m = Mass of an Electron ( kg )</em>

<em>v = Electron Release Speed ( m/s )</em>

<em>Ф = Work Function of Metal ( Joule )</em>

<em>q = Charge of an Electron ( Coulomb )</em>

<em>V = Stopping Potential ( Volt )</em>

Let us now tackle the problem!

<u>Given:</u>

Φ = 2.1 eV = 2 × 1.60 × 10⁻¹⁹ Joule = 3.20 × 10⁻¹⁹ Joule

<u>Unknown:</u>

fo = ?

<u>Solution:</u>

\Phi = h \times fo

3.20 \times 10^{-19} = 6.63 \times 10^{-34} \times fo

fo = ( 3.20 \times 10^{-19} ) \div ( 6.63 \times 10^{-34} )

\large {\boxed{fo = 4.83 \times 10^{14} ~ Hz} }

<h3>Learn more</h3>
  • Photoelectric Effect : brainly.com/question/1408276
  • Statements about the Photoelectric Effect : brainly.com/question/9260704
  • Rutherford model and Photoelecric Effect : brainly.com/question/1458544
  • Photoelectric Threshold Wavelength : brainly.com/question/10015690

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt

8 0
3 years ago
Read 2 more answers
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