Answer: 72200
Explanation:
First you must find the height for this is on an inclined hill using:
h=Lsin(angle) —> 28.0sin(11.0) = 5.34
Now you would just use the PE equation (mgh) because you are finding ME and when you starting from the top KE=0, showing that what ever answer you get from PE would equal the same for ME.
Using mgh:
m=1380
g=9.80
h=5.34
(1380)(9.8)(5.34)
=72218.16
*Rounding to the 3rd=72200
Hope this helps :)
Answer:4s^-1
Explanation:Tangential Acceleration=v^2/r=(20)²/100=400/100
Answer:
45.89m/s²
Explanation:
Given
Distance S = 305m
Time t = 3.64s
To get the acceleration during this run, we will apply the equation of motion:
S = ut+1/2at²
Substitute the given parameters into the formula and calculate the value of a
305 = 0+1/2 a(3.64)²
304 = 1/2(13.2496)a
304 = 6.6248a
a = 304/6.6248
a = 45.89m/s²
Hence the average acceleration during this run is 45.89m/s²
Chlorine gas or just chlorine?
