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DedPeter [7]
3 years ago
14

I'm sorry if any one seen that post about me saying I'm done with life and I don't want to be here it was my little cuzin @vicky

valadez123 and collagegirl
Physics
1 answer:
solniwko [45]3 years ago
8 0
I did not see the post. But if she actually needs help She can dm me. keep y'all's head up❤
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Explanation:

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3 years ago
Superman is flying 54.5 m/s when he sees
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348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.

To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations d=v_{0} t+\frac{at^{2} }{2} and v_{f} =v_{0} +at where d is distance, v_{0} is the initial velocity, v_{f} is the final velocity, t is time, and a is aceleration.

Superman's initial velocity is v_{0}=54.5\frac{m}{s}, and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know d, v_{0} and t, we have to find the aceleration a in order to find v_{f}.

From the equation d=v_{0} t+\frac{at^{2} }{2} we have to clear a, getting the equation as follows: a=\frac{2(d-v_{0}t) }{t^{2} }.

Substituting the values:

a=\frac{2(850m-54.5\frac{m}{s}.4.22s) }{(4.22s)^{2}}=69.63\frac{m}{s^{2}}

To find v_{f} we use the equation v_{f} =v_{0} +at.

Substituting the values:

v_{f} =54.5\frac{m}{s} +(69.63\frac{m}{s^{2}}.4.22s)=348.34\frac{m}{s}

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Where are the questions so that I can deliver a more accurate answer. 
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A certain wave motion has a frequency of 10 cycles / s and a wavelength of 3 m. so its propagation speed is
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3.5m is ur answer ask for more questions anytime
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