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4 years ago

How does a nuclear power plant produce electricity

1 answer:

6 0

It stores energy and uses it as power it can also be reffered to as a generator for power and lght used in citys or farms.

Brainliest????

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What is the net force necessary for a 1.6 x 103 kg car to accelerate forward at 2.0<br> m/s?

erastova [34]

Answer:31245.132

Explanation:

yeah

8 0

4 years ago

NHT0015

poizon [28]

Answer:

(1) 1×10⁻⁴

Explanation:

From the question,

α = (ΔL/L)/(ΔT)............. Equation 1

Where α = linear expansivity of the metal plate, ΔL/L = Fractional change in Length, ΔT = Rise in temperature.

Given: ΔL/L = 1×10⁻⁴, ΔT = 10°C

Substitute these values into equation 1

α = 1×10⁻⁴/10

α = 1×10⁻⁵ °C⁻¹ .

β = (ΔA/A)/ΔT................... Equation 2

Where β = Coefficient of Area expansivity, ΔA/A = Fractional change in area.

make ΔA/A the subject of the equation

ΔA/A = β×ΔT.......................... Equation 3

But,

β = 2α.......................... Equation 4

Substitute equation 4 into equation 3

ΔA/A = 2α×ΔT................ Equation 5

Given: ΔT = 5°C, α = 1×10⁻⁵ °C⁻¹

Substitute into equation 5

ΔA/A = ( 2)×(1×10⁻⁵)×(5)

ΔA/A = 10×10⁻⁵

ΔA/A = 1×10⁻⁴

Hence the right option is (1) 1×10⁻⁴

3 0

3 years ago

What do elements, compounds, and mixtures have in common?

Flura [38]

I think the answer is they are all made up atoms

8 0

3 years ago

A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid

tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

coefficient of friction (Uk) = ?

we can get the minimum coefficient of friction from the equation below

centrifugal force = frictional force

m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = $\frac{ r x ω^{2} }{g}$

where ω (angular velocity) = $\frac{2π}{time}$

= $\frac{2π }{5.5}$ = 1.14

Uk = $\frac{ 5.7 x 1.14^{2} }{9.8}$ = 0.76

6 0

4 years ago

Suppose you have a glider and a hanging mass that you wish to know the masses of but you do not have a triple-beam balance avail

AlladinOne [14]

Answer:

the choice of a glider to hanging mass is a ratio of 20.2

Explanation:

The Newton´s second law for glider is:

Fnet=Ma

T=Ma

The Newton´s second law for hanging mass is:

Fnet=ma

mag-T=ma

Replacing:

mag-Ma=ma (eq. 1)

Clearing a:

a=(mg)/(m+M)

The expression for motion is:

$y=vot+\frac{1}{2}at^{2}$

$H=0+\frac{1}{2}at^{2}$

Clearing a:

$a=\frac{2H}{t^{2} }$

Replacing values:

$a=\frac{2*0.75}{1.8^{2} } =0.46$

From eq. 1:

M/m=20.2

5 0

3 years ago