When was the international space station launched
1 answer:
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Answer:
<h2>i. 9J and </h2><h2>ii. -9J</h2>Explanation:
Please see attached the diagram and also the FBD for your reference.
Step one:
given data
Weight w1=20N
Distance s1=75cm= 0.75m
Weight w2=12N
Distance s2=75cm =0.75m
Clearly, we are asked to find the work done by gravity and the tension in the string.
we know that work is defined as force times the distance traveled
W=F*D
and to know the force we need the acceleration, seeing that the system is stationary the acceleration due to gravity 9.81m/s^2 is not needed here
i . Work done by gravity = w2*s2=12*0.75=9J
ii. The tension is equal but opposite = -9J
Answer:
The velocity of Dan is 1.13 m/s.
Explanation:
Given that,
Initial velocity of skateboard and Dan = 2.00 m/s
Velocity of skateboard = 7.00 m/s
Mass of Dan m= 40.0 kg
Mass of skateboard M= 7.00 Kg
Suppose How fast is Dan going as his feet hit the ground?
We need to calculate the initial velocity of Dan
Using conservation of momentum
Put the value into the formula
Hence, The velocity of Dan is 1.13 m/s.
Answer:
Explanation:
equation of wave is given by the following equation
y = (2.6 cm) sin[1.8 - (5.8 s-1)t].
Comparing it with standard form of wave
y = A sin ( ωt - kx )
we get
ω = 5.8
2πn = 5.8
n = .92 per second
kx = 1.8
k x 6 = 1.8
k = 0.3
= 0.3
λ = 20.9 cm