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3 years ago

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Compound X has a molar mass of 104.01·gmol−1 and the following composition: element mass % nitrogen 26.93% fluorine 73.07% Write

the molecular formula of X .

2 answers:

Stolb23 [73]3 years ago

4 0

Answer:

Explanation:

شخبارج فاطمه

Anuta_ua [19.1K]3 years ago

3 0

Answer: N2F4

Explanation:(NF2)x2 = N2F2

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Convert 27.7 kilometers to centimeters.

Stolb23 [73]

Answer:

The correct answer is - 2770000 cm.

Explanation:

1 kilometer = 1000 meter

1 meter = 100 centimeter

1 kilometer = 100*1000 cm

1 km = 100000 cm.

then,

27.7 kilometers = 2.77 × 10^6 centimeters

So, 27.7 kilometers = 27.7 × 100000

= 2.77 × 106 or 2770000 centimeters.

7 0

2 years ago

How many grams of PH3 will be produced if 6.0 l of H2 are used?

elena-s [515]

Mass of PH3= 6.086 g

<h3>Further explanation</h3>

Given

6.0 L of H2

Required

mass of PH3

Solution

Reaction

P4 + 6H2 → 4PH3

Assumed at STP ( 1 mol gas=22.4 L)

Mol of H2 for 6 L :

= 6 : 22.4 L

= 0.268

From the equation, mol PH3 :

= 4/6 x moles H2

= 4/6 x 0.268

= 0.179

Mass PH3 :

= 0.179 x 33,99758 g/mol

= 6.086 g

5 0

2 years ago

Using the model of the periodic table, which two elements pictured have similar chemical properties?

Murljashka [212]

Answer:

1 and 3

Explanation:

The vertical columns (groups) of the periodic table are arranged such that all its elements have the same number of valence electrons. All elements within a certain group thus share similar properties.

5 0

3 years ago

Read 2 more answers

What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm

Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u> <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

$n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}$

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = $5\times 196.96$ g

4.99 moles of gold contain = 984.8 g

Mass of ${3.01\times 10^{24}}$ atoms of gold = 984.5 g

<u>Part II :</u>

Density of Gold = $19.32 g/cm^{3}$

Volume of the cuboid = $length\times breadth\times height$

Volume of the gold bar = $6.00\times 4.25\times 2.00$

Volume of the gold bar = 51 $cm^{3}$

Using formula,

$Density = \frac{mass}{Volume}$

$Mass = Density\times Volume$

$Mass = 19.32 \times 51$

Mass = 985.32 g

So, A gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u> <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

3 0

3 years ago

Help now im not trying to fail

Alekssandra [29.7K]

Answer:

i cant see the whats in the picture

5 0

2 years ago

Read 2 more answers