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TEA [102]
2 years ago
9

Pick one please A. B. C. D.

Chemistry
2 answers:
Ahat [919]2 years ago
7 0

Answer:

B

Explanation:

just because it feels right and why not

guapka [62]2 years ago
3 0

Answer:

I would personally choose A but .....

Explanation:

flip a coin and the letter that came to your mind before you see it is the one to choose .

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Why Ammonia is nut dried by passing through concentrated H2SO4.​
STALIN [3.7K]

Answer:

Because it is absorbed by conc . H . SO , to form ammonium sulphate.

6 0
3 years ago
- Ibrahim and Emmanuel have been investigating the amount of copper sulfate that
nignag [31]

The boys can arrive at the conclusion that as temperature increases, a greater mass of copper sulfate is dissolved in water.

<h3>What is an experiment?</h3>

An experiment is a scientific investigation that seeks to obtain cause and effect relationships. There must be a dependent and an independent variable in every experiment.

The average of the temperature readings is; 20 + 30 + 40 + 50 + 60 + 70 + 80/7 =  50

They used an interval of 10 degrees for the temperature readings. The boys should have kept the heating time the same. The independent variable in this experiment is the temperature. The boys can arrive at the conclusion that as temperature increases, a greater mass of copper sulfate is dissolved in water.

Learn more about dependent and independent variables: brainly.com/question/967776

8 0
2 years ago
What are some lessons from
DaniilM [7]
That if we don’t separate our selves hundreds and thousands of people will die but if we stay apart it will resolve sooner
4 0
3 years ago
Read 2 more answers
Ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with
ankoles [38]

Answer:

n_{NH_3}=0.18molNH_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

H_3PO_4(aq)+3NH_3(l)\rightarrow (NH_4)_3PO_4

In such a way, considering the 3 to 1 molar relationship between ammonia and ammonium phosphate, the moles of ammonia result:

n_{NH_3}=0.060mol(NH_4)_3PO_4*\frac{3molNH_3}{1mol(NH_4)_3PO_4}\\n_{NH_3}=0.18molNH_3

Best regards.

8 0
3 years ago
A certain half-reaction has a standard reduction potential +0.80 V . An engineer proposes using this half-reaction at the anode
Strike441 [17]

Answer:

a. Minimum 1.70 V

b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

ε⁰ cell = ε⁰ reduction -  ε⁰  oxidation

Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the  oxidized species  0.80 V, thus

ε⁰ reduction -  ε⁰  oxidation ≥  ε⁰ cell

Since ε⁰  oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V )  ≥  0.90 V

⇒ ε⁰ reduction  ≥ 1.70 V

Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

8 0
3 years ago
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