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AleksAgata [21]
3 years ago
6

Answer this please thank you

Chemistry
1 answer:
jekas [21]3 years ago
4 0

Answer:

Heterozygous

Explanation:

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Amount of a substance (called the solute) that dissolves in a unit volume of a liquid substance (called the solvent) to form a saturated solution under specified conditions of temperature and pressure.Solubility is expressed usually as moles of solute per 100 grams of solvent.
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True. Ions can have a positive or negative charge.
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1. Baking soda and vinegar combined *
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3 years ago
How many dm³ of hydrogen,measured at s.t.p.,would be needed to reduce 47.7g of copper(II) oxide to copper?
GaryK [48]

Answer:

Option D. 13.44

Explanation:

We'll begin by calculating the number of mole in 47.7g of copper(II) oxide, CuO.

This can be obtained as follow:

Mass of CuO = 47.7 g

Molar mass of CuO = 63.5 + 16 = 79.5 g/mol

Mole of CuO =.?

Mole = mass /Molar mass

Mole of CuO = 47.7/79.5

Mole of CuO = 0.6 mole

Next, we shall write the balanced equation for the reaction. This is given below:

CuO + H2 —> Cu + H2O

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2 to produce 1 mole of Cu and 1 mole of H2O.

Next, we shall determine the number of mole of H2 needed to react completely with 0.6 mole of CuO.

This can be obtained as follow:

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2.

Therefore, 0.6 mole of CuO will also react with 0.6 mole of H2.

Finally, we shall determine the volume occupied by 0.6 mole of H2 at STP.

This can be obtained as follow:

1 mole of H2 occupied 22.4 dm³ at STP.

Therefore, 0.6 mole of H2 will occupy = 0.6 × 22.4 = 13.44 dm³.

Therefore, 13.44 dm³ of H2 is needed for the reaction.

4 0
3 years ago
How many moles of ScCl3 can be produced when 10.00 mol Sc react with 9.00 mol Cl2
Nuetrik [128]

Answer:

Moles of ScCl_3 = 6 moles

Explanation:

The reaction of Sc and Cl_2 to make ScCl_3 is:

2Sc+3Cl_2⇒2ScCl_3

The above reaction shows that 2 moles of Sc  can react with 3 moles of Cl_2 to form ScCl_3.

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of Cl_2 = Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 = 10 *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 =15 moles

So 15 moles of Cl_2 are required to react with 10 moles of Sc but we have 9 moles of Cl_2 , it means Cl_2 is limiting reactant.

Moles of ScCl_3=Given\  Moles\  of\ Cl_2 *\frac{2\  Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}

Moles\ of\  ScCl_3=9 *\frac{2\  Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}

Moles of ScCl_3= 6 moles

4 0
3 years ago
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