Answer:
Calcium (Ca) - will lose electrons
Sulfur (S) - will gain electrons
Carbon (C) could lose or gain electrons
Neon (Ne) Does not gain or lose electrons
Answer:
The concentration is
Explanation:
From the question we are told that
The voltage of the cell is 
Generally the reaction at the cathode is
the half cell voltage is V_c = 0.337 V
Generally the reaction at the anode is
the half cell voltage is V_a = -0.337 V
Gnerally the reaction of the cell is

At initial the voltage is V = 0 V
Generally the voltage of the cell at 25°C is
![E = V - \frac{0.0591}{n} log \frac{[Cu^{2+}] _a}{[Cu^{2+}]_c}](https://tex.z-dn.net/?f=E%20%3D%20%20V%20%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5BCu%5E%7B2%2B%7D%5D%20_a%7D%7B%5BCu%5E%7B2%2B%7D%5D_c%7D)
Here n is number of of electron and it is 2
So from the question we are told that one cell has a concentration 1.5 x 10-3 M
Let assume it is ![[Cu^{2+}]_c](https://tex.z-dn.net/?f=%5BCu%5E%7B2%2B%7D%5D_c)
So
![0.22= 0 - \frac{0.0591}{2} log \frac{[Cu^{2+}] _a}{ 1.5 * 10^{-3} }](https://tex.z-dn.net/?f=0.22%3D%20%200%20%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%20%5Cfrac%7B%5BCu%5E%7B2%2B%7D%5D%20_a%7D%7B%20%201.5%20%2A%2010%5E%7B-3%7D%20%7D)
=> ![-7.445 = log \frac{[Cu^{2+}] _a}{ 1.5 * 10^{-3} }](https://tex.z-dn.net/?f=-7.445%20%3D%20%20%20%20%20log%20%5Cfrac%7B%5BCu%5E%7B2%2B%7D%5D%20_a%7D%7B%20%201.5%20%2A%2010%5E%7B-3%7D%20%7D)
=> ![-7.445 = log [Cu^{2+}_a] - log [1.5*10^{-3}]](https://tex.z-dn.net/?f=-7.445%20%3D%20%20%20%20%20log%20%5BCu%5E%7B2%2B%7D_a%5D%20-%20log%20%5B1.5%2A10%5E%7B-3%7D%5D)
=> ![-7.445 + log [1.5*10^{-3} = log [Cu^{2+}_a]](https://tex.z-dn.net/?f=-7.445%20%20%2B%20log%20%5B1.5%2A10%5E%7B-3%7D%20%3D%20%20%20%20%20log%20%5BCu%5E%7B2%2B%7D_a%5D%20)
=> ![-7.445 - 2.824 = log [Cu^{2+}_a]](https://tex.z-dn.net/?f=-7.445%20%20-%202.824%20%3D%20%20%20%20%20log%20%5BCu%5E%7B2%2B%7D_a%5D%20)
Taking the antilog
=>
=>
Answer:
B.) and D.)
Explanation:
A.) is incorrect because the reaction technically never stops if the system remains in tact. Rather, there is just an equal amount of forward and reverse reactions occurring. This means that the overall concentrations of the reactants and products stays the same.
B.) is correct because when the concentrations of the reactants and products remain unchanged, then equilibrium is reached.
C.) in incorrect because, at this point, the concentrations of the reactants are still decreasing and the products are still increasing. If point 2 is specifically referencing the intersection of the lines, this cross symbolizes equal concentrations of the reactants and product. Keep in mind that equal concentrations does not equal equilibrium.
D.) is correct because a reaction moving forward means that mostly product is being created. In other words, the concentration of the product should be increasing. Meanwhile, the concentration of the reactants decrease because they are being used to create the product. As seen in the graph, the product (H₂O₂) is rapidly increasing in concentration. Meanwhile, the concentrations of the reactants (O₂ and H₂O) are decreasing as they would in a forward reaction.
Answer:
Option D. 1×10¯¹⁰ M
Explanation:
From the question given above, the following data were obtained:
pH = 10
Hydrogen ion concentration, [H+] =?
The hydrogen ion concentration, [H+] of the Ba(OH)2 solution can be obtained as follow:
pH = – Log [H+]
pH = 10
10 = – Log [H+]
Divide both side by – 1
– 10 = Log [H+]
Take the antilog of – 10
[H+] = antilog (– 10)
[H+] = 1×10¯¹⁰ M
Therefore, the hydrogen ion concentration, [H+] of the Ba(OH)2 solution is 1×10¯¹⁰ M
It's in the periodic table.
See the attached picture. The number below 'Zn' is the molar mass. The closest answer choice is 65.38