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kipiarov [429]
4 years ago
13

Anyone good at science?

Physics
2 answers:
frozen [14]4 years ago
5 0
<span>In a transverse wave, the motion of the disturbance is "Parallel" to the wave motion.

In short, Your Answer would be Option B

Hope this helps!</span>
V125BC [204]4 years ago
5 0

Think about the definition of a transverse wave.

The answer is A. 
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A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
If a sample of a(
Otrada [13]
Idkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidk
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3 years ago
Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tig
Andru [333]
I=2.27 x 10 to the 3rd power A
5 0
3 years ago
What is an example of a high amplitude sound, and an example of a low amplitude sound? 
Sergeu [11.5K]
High amplitude sound would be music, radio, or earthquakes.
Low amplitude sound would be a breeze or wind.
7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP URGENT!!!!!
coldgirl [10]

Answer:

B

i am not fully sure but i believe its the most accurate its either A or B

5 0
3 years ago
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