All categories

4 years ago

Anyone good at science?

2 answers:

5 0

In a transverse wave, the motion of the disturbance is "Parallel" to the wave motion.

In short, Your Answer would be Option B

Hope this helps!

V125BC [204]4 years ago

5 0

Think about the definition of a transverse wave.

The answer is A.

You might be interested in

An empty train car of mass 2.0 x 10^4 kg coasts along at 10 m/s. A 3000-kg boulder is suddenly dropped vertically into the car.

Zepler [3.9K]

Answer:8.69 m/s

Explanation:

Given

mass of Empty train $m=2\times 10^4 kg$

velocity of car $v=10 m/s$

mass of Boulder $M=3000 kg$

Since no External force is acting therefore conserving Momentum

Train and boulder moves with same velocity after collision

$m v=(M+m)v'$

$2\times 10^4\times 10=(2\times 10^4+3000)v'$

$v'=\frac{20,000\times 10}{23000}$

$v'=8.69 m/s$

8 0

3 years ago

If electrons are taken away from an atom, the atom develops a _________ charge.

VARVARA [1.3K]

Answer:

a positive charge

Explanation:

5 0

4 years ago

Read 2 more answers

Show the relationship between the quantity of matter and the mass of objects

IRISSAK [1]

Answer:

actually quantity of matter present in a body is its mass.

3 0

3 years ago

How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?

Aleonysh [2.5K]

Solution :-

Given that ,

Initial Velocity of car = 44km / hr.
Final Velocity of car = 0km / hr.
Acceleration = -5km/hr².

To Find :

Time taken to stop the car .

So , here use first equⁿ of motion which is ,

$\boxed{\red{\bf\dag v = u + at }}$

where ,

v is final Velocity.
u is Initial velocity.
a is acceleration.
t is time taken.

Now , substituting the respective values ,

$\tt:\implies v=u+at$

$\tt:\implies 0 = 44 + (-5)t$

$\tt:\implies -44 = -5t$

$\tt:\implies t=\dfrac{44}{5}$

$\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}$

$\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}$

6 0

3 years ago

The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a u

kompoz [17]

Answer:

Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).

Explanation:

Given:

Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s

first to find Electric Force

F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)

We also have F=ma

⇒ a = F/m = - 8 × 10⁻⁵ N / 10 × 10⁻⁵ kg = -8 m/s² ( -ve sign shows that the particle is accelerated opposite to positive x- direction)

Now according the first equation of Motion.

Vf = Vi + at

Vf = 20 m/s + -8 m/s² × 5 s

Vf= -20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction)

6 0

3 years ago