1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dlinn [17]
3 years ago
15

You place the spring vertically with one end on the floor. You then lay a 1.60 kg book on top of the spring and release the book

from rest. Find the maximum distance the spring will be compressed.
Physics
1 answer:
malfutka [58]3 years ago
4 0

Answer:

Compression in the spring, x = 3.7 cm

Explanation:

It is given that,

Mass of the book, m = 1.6 kg

It can be assumed the spring constant of the spring is, k = 840 N/m

As the book moves down, the change in potential energy of the book is converted to spring potential energy of compression. The mathematical expression is as follows :

\dfrac{1}{2}kx^2=mgx

x=\dfrac{2mg}{k}

x=\dfrac{2\times 1.6\ kg\times 9.8\ m/s^2}{840\ N/m}  

x = 0.037 meters

or

x = 3.7 cm

So, the spring is compressed to a distance of 3.7 cm. Hence, this is the required solution.

You might be interested in
A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. (a) What is the acceleration exp
givi [52]
Yes the plot dose make it with out baking out
7 0
3 years ago
A 4.6 g lead bullet moving at 278 m/s strikes a steel plate and stops. If all its kinetic energy is converted to thermal energy
iren2701 [21]

Answer:

ΔT = 302 °c

Explanation:

mass (m) = 4.6 g = 0.0046 kg

velocity (v) = 278 m/s

specific heat of lead (c) = 128 J/kg. °c

kinetic energy = 0.5 mx v^{2}

kinetic energy = 0.5 x 0.0046 x 278^{2}

kinetic energy = 177.8 J

since all the kinetic energy is converted to thermal energy,

kinetic energy = thermal energy (E) = 177.8 J

thermal energy = m x c x ΔT

where ΔT is the temperature change

177.8 = 0.0046 x 128 x ΔT

ΔT = 177.8 / 0.59

ΔT = 302 °c

3 0
3 years ago
If the earth's magnetic field has strength 0.50 gauss and makes an angle of 20.0 degrees with the garage floor, calculate the ch
lys-0071 [83]

Answer:

ΔΦ = -3.39*10^-6

Explanation:

Given:-

- The given magnetic field strength B = 0.50 gauss

- The angle between earth magnetic field and garage floor ∅ = 20 °

- The loop is rotated by 90 degree.

- The radius of the coil r = 19 cm

Find:

calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.

Solution:

- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.

- The strength of magnetic field B and the are of the loop A remains constant. So we have:

                         Φ = B*A*cos(θ)

                         ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )

- The initial angle θ_1 between the normal to the coil and B was:

                         θ_1  = 90° -  ∅

                         θ_1  = 90° -  20° = 70°

The angle θ_2 after rotation between the normal to the coil and B was:

                         θ_2  =  ∅

                         θ_2  = 20°

- Hence, the change in flux can be calculated:

                        ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )

                        ΔΦ = -3.39*10^-6

                       

8 0
3 years ago
A rectangular metal tank with an open top is to hold 171.5 cubic feet of liquid. what are the dimensions of the tank that requir
Semmy [17]
To minimize the material usage we have to have the volume requested with the minimum surface area.
The volume is:
171.5 =xyz
And the surface is:
S=xy+2xz+2yz
From the first equation we get:
z=\frac{171.5}{xy} ; k=171.5\\ z=\frac{k}{xy}\\
I will use k instead of a number just for the conveince.
We plug this into the second equation and we get:
S=xy+2k\frac{1}{x}+2k\frac{1}{y}
To find the minimum of this function we have to find the zeros of its first derivative.
Sx will denote the first derivative with respect to x and Sy will denote the first derivative with respect to Sy.
S_x=y-2k\frac{1}{x^2}\\ S_y=x-2k\frac{1}{y^2}
Now let both derivatives go to zero and solve the system (this will give us the so-called critical points).
0=y-2k\frac{1}{x^2}\\
0=x-2k\frac{1}{y^2}\\
y=2k\frac{1}{x^2}\\
x=2k\frac{1}{y^2}\\
Now we plug in the first equation into the other and we get:
x=\frac{\frac{2k}{1}}{\frac{4k^2}{x^4}}\\
x^3=2k\\
x=(2\cdot171.5)^{1/3}\\
x=7

Now we can calculate y:
y=2k\frac{1}{x^2}\\
y=2\cdot 171.5\frac{1}{7^2}=7
And finaly we calculate z:
z=\frac{171.5}{xy}\\
z=\frac{171.5}{7\cdot7}=3.5
And finaly let's check our result:
V=xyz=7\cdot7\cdot3.5=171.5
4 0
3 years ago
A cat runs 6m in 4seconds what is it speed
gayaneshka [121]

Explanation:

<h2>expation!!!!!!!!!!!!!!!!!!!!!!!!!! $$!!!!!!!!!!!!!!! explantion bbbnb</h2>
6 0
3 years ago
Other questions:
  • When astronomers observe the spectra of distant galaxies,they notice that the hydrogen emission lines are shifted noticeably tow
    8·1 answer
  • A box weighing 4.0 N is lifted 3.0 meters. How much work is done on the box?
    14·1 answer
  • One container has 100 ml of water and a second container has 1000 ml of water. If the temperature in both containers is 22 oc (7
    13·1 answer
  • When the car carrying the unbelted driver crashes, what brings the driver to a stop
    9·1 answer
  • A rectangular solid made of carbon has sides of lengths 1.0 cm, 2.0 cm, and 4.0 cm, lying along the x, y, and z axes, respective
    15·1 answer
  • How high is an object lifted if the total work done on it is 125 J and the force required to lift the object is 25 N? Use the eq
    11·1 answer
  • A body having uniform velocity has zero acceleration? give reason​
    9·2 answers
  • Plsss help I will mark brainlist
    15·2 answers
  • When a piece of iron or mass 78 gm is put in a graduated cylinder containing 100 cm cube of water the reading of the cylinder be
    5·1 answer
  • What idea about work and force does the diagram describe? Explain your answer.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!