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Gnoma [55]
3 years ago
15

Suppose that a car traveling to the west (-x direction) begins to slow down as it approaches a traffic light. Make a statement c

oncerning its acceleration.a) The car is decelerating and its acceleration is positive.b) The car is decelerating, and its acceleration is negative.c) The acceleration is zero.d) A statement cannot be made using the information given.
Physics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

The car is decelerating and its acceleration is negative.

Explanation:

First thing to consider. The car traveling direction is not important to answer the question.

Second, there are two affirmations on each sentence. So, lets take definitions:

Deceleration: Reducing the acceleration, from one value to another. No matter if the acceleration for the moment is positive or negative.

Acceleration negative: the driver is applying a force to make speed=0, the sign of this force must negative in order for the car to stop, other way it will go faster. Acceleration is the change rate of speed, if the speed is going down, the total acceleration until cars stops must be negative.

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4. An object is thrown vertically upward with a speed of 25 m/s. How much time passes before it
vlada-n [284]

Answer:

<em>Option b is correct: 4.1 s</em>

Explanation:

<u>Vertical Launch</u>

An object launched thrown vertically upward where air resistance is negligible, reaches its maximum height in a time t, given by the equation:

\displaystyle t=\frac{v_o}{g}\qquad\qquad[1]

Where vo is the initial speed and g is the acceleration of gravity g=9.8 m/s^2.

Once the object reaches that point, it starts a free-fall motion, whose speed is (downward) given by:

v_f=g.t\qquad\qquad[2]

The object considered in the question is thrown with vo=25 m/s. The time taken to reach the maximum height is given by [1]:

\displaystyle t=\frac{25}{9.8}=2.551\ sec

The object starts its falling motion and at some time, it has a speed of vf=15 m/s. Let's find the time by solving [2] for t:

\displaystyle t=\frac{15}{9.8}=1.531\ sec

The total time taken by the object to go up and down is

t_t=2.551\ s+1.531\ s=4.081\ s

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