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Fudgin [204]
4 years ago
13

The monomer used as the building block in polyethylene is? Ethene, ethane, monoethane, amino acids?

Physics
1 answer:
LuckyWell [14K]4 years ago
6 0
<span>it's ethene and not an amino acid!!! amino acids form proteins as their polymers. </span>
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A scuba diver, submerged under water looks up and seessunlight
maw [93]

Answer:

41.7975\ ^{\circ}

Explanation:

n_2 = Refraction index of water = 1.333

n_1 = Refraction index of air = 1

\theta_2 = Angle of sunlight = 30°

From Snell's law we have

\dfrac{n_1}{n_2}=\dfrac{sin\theta_2}{sin\theta_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{n_2sin\theta_2}{n_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{1.333sin30}{1}\\\Rightarrow \theta_1=41.7975\ ^{\circ}

The angle measured from the vertical does the sunlight strike thesurface of the water is 41.7975\ ^{\circ}

5 0
3 years ago
Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with
Ann [662]

Answer:

The value is  v  =  2 \ m/s

Explanation:

From the question we are told that

   The velocity of the each of the three cars is u_1 = u_2 = u_3 =  2 \  m/s

    The velocity of the fourth car is  u_4 =  4 \ m/s

    The initial velocity of the fifth car u_5 =  0 \ m/s

Generally from the law of momentum conservation we have that

    m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 =  [m_1   + m_2 + m_3 +m_4+ m_5]v

Given that the cars are identical then their mass will be the same

i.e

    m_1 =m_2 = m_3 = m_4 = m_5 =  m

=>   [u_1 + u_2 +  u_3 +u_4 + u_5]m =  5mv

=>   2+ 2 +  2 +4 + 0 =  5v

= >   v  =  2 \ m/s

8 0
3 years ago
How do i do about how to do the doing of how about how the logic of the person below me is bad but actually isnt bad because the
olga55 [171]

Answer:

i think that bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad but actually isnt bad because their good at being bad but they are actually bad, that makes me say, its A

Answer:

Explanation:



Explanation:

5 0
3 years ago
Read 2 more answers
Which products are formed when ethane (C2H6) undergoes combustion?
ANEK [815]

Answer:

C.

Explanation:

It is C.

4 0
3 years ago
Read 2 more answers
Two charges are in the configuration indicated here. The first charge, Q1 = –1.00 μC, sits at the origin. The second charge, Q2
blagie [28]

Answer:

E_{net} = 3.6 \times 10^4 N/C

Explanation:

As the two charges Q1 and Q2 are placed at some distance apart

so the electric field at mid point will be twice the electric field due to one charge

Because here the two charges are of opposite sign so here the electric field at mid point will be added due to both

so here we have

E_{net} = 2E

E_{net} = 2(\frac{kQ}{r^2})

distance of mid point from one charge is given as

r = \frac{\sqrt{1^2 + 1^2}}{2}

E_{net} = 2 (\frac{(9\times 10^9)(1\times 10^{-6})}{(\frac{1}{\sqrt2})^2}

E_{net} = 3.6 \times 10^4 N/C

5 0
3 years ago
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