2H2O -> 2H2 + O2
Stoichiometric ratio:
2 : 2 : 1
H2O : O2
2 : 1
Mass of 1 mol of H2O = [(2 x 1) + 16] g = 18g
18g of H2O = 1 mol of H2O
90g of H2O = 90g x 1 mol / 18g
= 5 mol of H2O
2 mol of H2O : 1 mol of O2
5 mol of H2O : 5/2 mol of O2
1 mol of O2 = 22.4 L of O2
5/2 mol of O2 = 5/2 mol x 22.4 L / 1 mol
= 56 L of O2
I guess it is called an Equation !!
Answer:
1.7 M
Explanation:
Concentration is the number of moles of solute dissolved in 1 L of solution
Concentration = number of moles of solute / volume of solution
Number of moles of solute needs to be calculated first
Mass of methanol - 12.5 g
Molar mass of methanol - 32 g/mol
Number of methanol moles - 12.5 g / 32 g/mol = 0.39 mol
Therefore concentration is = 0.39 mol / 0.230 L = 1.7 mol/L
Concentration is 1.7 M
A control group is the group in an experiment that does not receive any sort of change, to then be compared to the other treated objects at the end of the study.