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Rasek [7]
3 years ago
14

!!Help ASAP!!! Imagine you have just baked a pizza in the oven. You've only let it cool for a minute, but you're hungry and you

want to take a bite. To minimize your chances of burning your mouth, should you take a bite with a lot of sauce on it or a bite near the crust that contains very little sauce? Explain your answer based on what you have learned about thermal energy and specific heat capacity. (5 points) Think about how the specific heat capacity of the watery sauce compares with that of the much drier pizza crust.
Chemistry
2 answers:
OleMash [197]3 years ago
8 0

Answer:

bite where there is less sauce.

Explanation:

i just ate a pizza and it worked

meriva3 years ago
3 0

Answer:

take a bite near crust

Explanation:

because the sauce is still hot so u will get burned

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Select the correct answer from each drop down menu.
lukranit [14]

Two German chemists, Justus von Liebig (1803–1873) and Friedrich Wöhler (1800–1882), were responsible for the emergence of organic chemistry in the early nineteenth century. Their quantitative analytical methods helped establish the constitution of newly isolated and synthesized carbon compounds.

4 0
2 years ago
A 1.00 g sample of a metal X (that is known to form X ions in solution) was added to 127.9 mL of 0.5000 M sulfuric acid. After a
Semenov [28]

<u>Answer:</u> The metal having molar mass equal to 26.95 g/mol is Aluminium

<u>Explanation:</u>

  • To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

Molarity of NaOH solution = 0.5000 M

Volume of solution = 0.03340 L

Putting values in equation 1, we get:

0.5000M=\frac{\text{Moles of NaOH}}{0.03340L}\\\\\text{Moles of NaOH}=(0.5000mol/L\times 0.03340L)=0.01670mol

  • The chemical equation for the reaction of NaOH and sulfuric acid follows:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+H_2O

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of sulfuric acid

So, 0.01670 moles of NaOH will react with = \frac{1}{2}\times 0.01670=0.00835mol of sulfuric acid

Excess moles of sulfuric acid = 0.00835 moles

  • Calculating the moles of sulfuric acid by using equation 1, we get:

Molarity of sulfuric acid solution = 0.5000 M

Volume of solution = 127.9 mL = 0.1279 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

0.5000M=\frac{\text{Moles of }H_2SO_4}{0.1279L}\\\\\text{Moles of }H_2SO_4=(0.5000mol/L\times 0.1279L)=0.06395mol

Number of moles of sulfuric acid reacted = 0.06395 - 0.00835 = 0.0556 moles

  • The chemical equation for the reaction of metal (forming M^{3+} ion) and sulfuric acid follows:

2X+3H_2SO_4\rightarrow X_2(SO_4)_3+3H_2

By Stoichiometry of the reaction:

3 moles of sulfuric acid reacts with 2 moles of metal

So, 0.0556 moles of sulfuric acid will react with = \frac{2}{3}\times 0.0556=0.0371mol of metal

  • To calculate the molar mass of metal for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Mass of metal = 1.00 g

Moles of metal = 0.0371 moles

Putting values in above equation, we get:

0.0371mol=\frac{1.00g}{\text{Molar mass of metal}}\\\\\text{Molar mass of metal}=\frac{1.00g}{0.0371mol}=26.95g/mol

Hence, the metal having molar mass equal to 26.95 g/mol is Aluminium

6 0
3 years ago
Determine the number of molecules in 43.9 g of carbon tetrachloride
ddd [48]

Answer: There are about 0.28 molecules in 43.9 g of carbon tetrachloride. If you are rounding up, it would be 0.3

Explanation:

7 0
2 years ago
Find the density of an object that has a mass of 5 kg and a<br> volume of 50 cm3.
iren2701 [21]
  • Mass=5kg=5000g
  • Volume=50cm^3

\\ \rm\longmapsto Density=\dfrac{Mass}{Volume}

\\ \rm\longmapsto Density=\dfrac{5000}{50}

\\ \rm\longmapsto Density=100g/cm^3

4 0
2 years ago
Some bleaches contain hydrogen peroxide as their active ingredient, while others contain sodium hypochlorite. Both these chemica
pshichka [43]
B) oxygen, because oxygen is the only element that is in both chemical formulas.
3 0
3 years ago
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