Answer:
yes, if you're going at 120 km and you saw the wall that late then it wouldn't me possible to decrease 12 meters in 5 seconds and not hit the wall that's only 60 meters away
Explanation:
Answer:
m = 3.75 [kg]
Explanation:
We must remember that momentum is defined as the product of mass by Velocity, therefore it can be represented by means of the following equation.
where:
P = momentum = 93.75 [kg*m/s]
m = mass [kg]
v = velocity = 25 [m/s]
Now replacing, we can clear the mass:
![P=m*v\\m=P/v\\m=93.75/25\\m=3.75 [kg]](https://tex.z-dn.net/?f=P%3Dm%2Av%5C%5Cm%3DP%2Fv%5C%5Cm%3D93.75%2F25%5C%5Cm%3D3.75%20%5Bkg%5D)
Answer:
The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.
Explanation:
Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.
Answer:
L = 40 cm
Explanation:
A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens
M = - L / f₀ (25 cm /
)
where fo and fe are the focal lengths of the objective and eyepiece, 25 cm is the near vision distance and L is the length of the microscope
L = - M f_{o} f_{e} / 25
let's calculate
L = - (-100) 2 5/25
L = 40 cm
Momentum and inertia,
Momentum=P. P=MV. M=mass and V=velocity. Mass is related to inertia so inertia=F. F=MA. A=acceleration.
