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deff fn [24]
3 years ago
14

The quotient of x and 5 is equal to 35 (write and solve an equation based off the verbal phrase)

Mathematics
2 answers:
Maksim231197 [3]3 years ago
6 0
5x=35
35/5=7
x=7

hope this helps
Y_Kistochka [10]3 years ago
5 0

Answer:

The solution is, x = 175

Step-by-step explanation:

Given phrase,

The quotient of x and 5 is equal to 35,

∵ Quotient of x and 5 = \frac{x}{5}

So, the required equation is,

\frac{x}{5}=35

Multiply both sides by 5,

x=35\times 5 = 175

Hence, the solution of the given equation is, x = 175.

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Suppose that is in standard position and the given point is on the terminal side of 0. Give the exact value of the indicated tri
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Answer:

  12/13

Step-by-step explanation:

The length of the segment from the origin to the terminal point is ...

  r = √((-5)² +12²) = √169 = 13

The sine of the angle is the ratio of the y-coordinate to this distance

  sin(θ) = y/r = 12/13

_____

Additional comment

The other trig functions are ...

  cos(θ) = x/r = -5/13

  tan(θ) = y/x = -12/5

This is a 2nd-quadrant angle, where the sine is positive, but the cosine and tangent are negative.

6 0
2 years ago
the areas of the world's oceans are listed in the table order the oceans according to their area from least to greatest.
agasfer [191]
Pacific ocean is the biggest ocean
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3 years ago
WHAT DID LEAH DO WRONG <br> -5.25 = -25/100= -1/4
stepan [7]

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Is x-2 a factor of 4x^5 +5x^4 +1?
nordsb [41]

Answer:

No

Step-by-step explanation:

By the Factor theorem

If (x - h) is a factor of f(x) then f(h) = 0

Here (x - 2) with h = 2 and f(x) = 4x^{5} + 5x^{4} + 1 , then

f(2) = 4(2)^{5} + 5(2)^{4} + 1

     = 4(32) + 5(16) + 1

     = 128 + 80 + 1

     = 209

Since f(2) ≠ 0 then ( x - 2) is not a factor

 

8 0
3 years ago
"assume that s is a non-empty set of real numbers which is bounded above and lambda is the least upper bound. Prove that for all
s2008m [1.1K]

By definition, if \lambda is the least upper bound of the set S, it means two thing:

  • \forall x \in S,\ x \leq \lambda
  • \forall \varepsilon>0,\ \exists x \in S:\ x>\lambda-\varepsilon

In other words, the least upper bound of a set is greater than or equal to every single element of the set, but it is "close enough" to the elements of the set, because you guaranteed to find elements in the set between \lambda-\varepsilon and \lambda

For example, pick S = [1,10). Obvisouly, the least upper bound is \lambda = 10. In fact, every number in [1,10) is smaller than 10, but as soon as you take away something from 10, say 0.01, you get 9.99, and there are elements in S greater than 9.99, say 9.9999.

So, the claim is basically proven by definition: if \beta < \lambda, let 0 < \delta = \lambda - \beta. By definition, there exists \alpha \in S:\ \alpha > \lambda - \delta.

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