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2 years ago

How many moles of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)

Chemistry

1 answer:

yuradex [85]2 years ago

7 0

Answer:

0.20 mol

Explanation:

Let's consider the reduction of iron from an aqueous solution of iron (II).

Fe²⁺ + 2 e⁻ ⇒ Fe

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

5.6 g × 1 mol/55.85 g = 0.10 mol

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are

0.10 mol Fe × 2 mol e⁻/1 mol Fe = 0.20 mol e⁻

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What is the sum of the coefficients when the equation is balanced with the smallest whole numbers? __BaCl2 + __Fe2(SO4)3 → __FeC

aliina [53]

Explanation:

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2 years ago

How much heat is released when 6.00 g of methane is combusted using the reaction below? CH4 + 2O2 ? CO2 + 2H2O ?Hrxn = -890. KJ

goblinko [34]

Answer : The amount of heat released is, -121.04 KJ

Solution : Given,

Enthalpy of reaction, $\Delta H_{rxn}$ = -890 KJ

Mass of methane = 6 g

Molar mass of methane = 44 g/mole

First we have to calculate the moles of methane.

$\text{Moles of methane}=\frac{\text{Mass of methane}}{\text{Molar mass of methane}}=\frac{6g}{44g/mole}=0.136moles$

The given balanced reaction is,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

From the balanced reaction we conclude that

1 mole of methane releases heat = -890 KJ

0.136 moles of methane releases heat = $\frac{0.136moles}{1mole}\times -890KJ=-121.04KJ$

Therefore, the amount of heat released is, -121.04 KJ

8 0

2 years ago

Read 2 more answers

How many grams of k2so4 would you need to prepare 1500 g of 5.0% k2so4 solution?

son4ous [18]

Data Given:
% w/w = 5 %

Solution weight = 1500 g

Solute weight = ?

Formula Used:
% w/w = (Mass of Solute / Mass of Solution) × 100

Solving for Mass of Solute,

Mass of Solute = (% w/w × Mass of Solution) ÷ 100

Mass of Solute = (5 × 1500 g) ÷ 100

Mass of Solute = 75 g K₂SO₄

5 0

2 years ago

Help look at image thanks

Virty [35]

Answer:

0 percent chance.

Explanation:

If it is a male then the mom has to be a carrier or have the trait because the dad will pass on a Y, and the trait for colorblindness is linked to the X. If it is a female, she needs 2 of those traits (one from each parent), and since the mom cannot give one, there is not a chance of the kids having colorblindness.

5 0

2 years ago

A solution contains 10.6 g of glucose. How many moles of glucose are present? How many molecules of glucose are present? How man

spin [16.1K]

Answer:

- $moles=0.0588mol\ Glucose$

- $molecules=3.54x10^{22} molecules \ Glucose$

- $atoms \ C=2.13x10^{23}atoms \ C$

Explanation:

Hello,

In this case, by knowing molar mass of glucose is 180.156 g/mol, we can apply the following mole-mass-particles relationships in order to compute the moles, molecules and carbon atoms in the 10.6-g sample of glucose:

- Moles:

$moles=10.6g\ Glucose*\frac{1mol\ Glucose}{180.156g\ Glucose}\\\\moles=0.0588mol\ Glucose$

- Molecules: we also use Avogadro's number.

$molecules=10.6g\ Glucose*\frac{1mol\ Glucose}{180.156g\ Glucose}*\frac{6.022x10^{23} molecules \ Glucose}{1mol\ Glucose} \\\\molecules=3.54x10^{22} molecules \ Glucose$

- Carbon atoms: here, particularly, one mole of glucose has six moles of carbon atoms, thus:

$atoms\ C=10.6g\ Glucose*\frac{1mol\ Glucose}{180.156g\ Glucose}*\frac{6molC}{1mol\ Glucose} *\frac{6.022x10^{23}atoms \ C}{1molC} \\\\atoms \ C=2.13x10^{23}atoms \ C$

Regards.

7 0

2 years ago