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3 years ago

Anhydrous calcium chloride is used after washing your organic product with water. the purpose of this step is to:

2 answers:

7 0

The purpose of washing the organic product that contains water with anhydrous calcium chloride is to remove water from the organic product, thereby, increasing its purity. Calcium chloride is known to be one of the most effective drying agents together with sodium sulfate and magnesium sulfate. It is especially used for hydrocarbons. It is an inorganic salt that readily takes up the water from the organic product.

Brrunno [24]3 years ago

5 0

Anhydrous solids are the crystallized crystals when the hydrate form of the compound undergoes crystallization. Hence, when an anhydrous salt is placed in an aqueous environment, it will absorb water in order to be a hydrate once again. Thus, anhydrous calcium chloride is used to absorb the water to separate it from the organic product.

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Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.

The expression of rate of formation is:

$\frac{d(NOBr)}{dt}=r_{2}$

= $k_{2}[NOBr_{2}][NO]$ (1)

Now, consider that the fast step is always is in equilibrium. Therefore, $r_{1}=0$

$k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]$

$[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]$

Substitute the value of $[NOBr_{2}]$ in equation (1), we get:

$\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]$

= $k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]$

= $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$

Thus, rate law of formation of $NOBr$ in terms of reactants is given by $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$ .

4 0

3 years ago

Find the area given rectangle.

seraphim [82]

Answer:

The perimeter of a Rectangle P= 2(l + b)

Area of a Rectangle A = l × b

3 0

3 years ago

Which equation or rule can be used to estimate the pseudo-critical properties of mixtures based on the pure-component critical c

sveticcg [70]

Answer:

c. Kay's rule

Explanation:

Kay's rule -

The rule is used to determine the pseudo reduced critical parameters of mixture , with the help of using the critical properties of the components of a given mixture .

The equation for Kay's rule is as follows ,

PV = Z RT

Where Z = The compressibility factor of the mixture .

Hence from the given options , the correct answer is Kay's rule .

5 0

3 years ago

Calculate the mass of each element in the

Lelechka [254]

Answer:

For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively

Explanation:

The computation of the mass of each element is given below:

As we know that

A1 mole of ammonium nitrate i.e. 2 mol N, 4 mol H, 3 mol

Now we multiply each of above by the molar masses

For N

= 14.0 g/mol × 2

= 28.0 gN

For H

= 1.0 g/mol × 4

= 4.0 gN

ANd, for O

= 16.0 g/mol × 3

= 48.0 gN

Hence, For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively

7 0

3 years ago

What would the mass of 7 red apples be in kilograms?

Bogdan [553]

Answer:

I think it would be at 0.7 kg mass of the sun

8 0

3 years ago