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mixas84 [53]
3 years ago
12

What is the relationship between Celsius and kelvin

Chemistry
1 answer:
Inga [223]3 years ago
4 0

The relationship between Celsius and kelvin is that degrees Kelvin is equal to degrees Celsius + 273.15. That means that the freezing point of water (0°C) is 273.15° kelvin. This makes an additive relationship between the two quantities, so quantities such as the boiling point and freezing point of water are the same distance apart on the Kelvin scale (100 degrees). This means that kelvin has the same magnitude as Celsius.

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A solution of salt water is boiled. The water evaporates and solid salt remains. Which statement is true?
Scorpion4ik [409]
C because neither the water or salt have changed their molecular structure. H2O is still H2O and NaCl is still NaCl.
4 0
4 years ago
Orbital notation of h
shutvik [7]

Answer: in the box, put an arrow facing up. Below the box, write 1s

Explanation:

8 0
3 years ago
A solution is prepared from 4.5701 g of magnesium chloride and 43.238 g of water. The vapor pressure of water above this solutio
balandron [24]

Answer:

i = 2.483

Explanation:

The vapour pressure lowering formula is:

Pₐ = Xₐ×P⁰ₐ <em>(1)</em>

For electrolytes:

Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ

Where:

Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

<em>i = 2.483</em>

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I hope it helps!

4 0
3 years ago
Below is a proposed mechanism for the decomposition of H2O2. H2O2 + I– → H2O + IO– slow H2O2 + IO– → H2O + O2 + I– fast Which of
Savatey [412]

Answer: Option (d) is the correct answer.

Explanation:

The given equations as as follows.

       H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}           (slow)

       H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + O_{2} + I^{-}

Therefore, overall reaction equation will be as follows.

     2H_{2}O_{2} + I^{-} + IO^{-} \rightarrow 2H_{2}O + O_{2} + IO^{-} + I^{-}

So, cancelling the spectator ions then the equation will be as follows.

         H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

        H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}

                 Rate law = k[H_{2}O_{2}][I^{-}]

Hence, the reaction is first order with respect to [I^{-}] and it is also first order reaction with respect to [H_{2}O_{2}].

Also, [I^{-}] acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is IO^{-} is a catalyst.

6 0
3 years ago
A lab requires 3.50L of a 2.0M solution of HCl. What volume of a 6.0M solution is needed to make this solution?
Alchen [17]
The answer is 1.167L of 6.0M solution.

4 0
3 years ago
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