C because neither the water or salt have changed their molecular structure. H2O is still H2O and NaCl is still NaCl.
Answer: in the box, put an arrow facing up. Below the box, write 1s
Explanation:
Answer:
i = 2.483
Explanation:
The vapour pressure lowering formula is:
Pₐ = Xₐ×P⁰ₐ <em>(1)</em>
For electrolytes:
Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ
Where:
Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)
4.5701g of MgCl₂ are:
4.5701g ₓ (1mol / 95.211g) = 0.048000 moles
43.238g of water are:
43.238g ₓ (1mol / 18.015g) = 2.400 moles
Replacing in (1):
0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm
0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)
2.4mol + i*0.048mol = 2.4mol / 0.9527
2.4mol + i*0.048mol = 2.5192mol
i*0.048mol = 2.5192mol - 2.4mol
i = 0.1192mol / 0.048mol
<em>i = 2.483</em>
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I hope it helps!
Answer: Option (d) is the correct answer.
Explanation:
The given equations as as follows.
(slow)
Therefore, overall reaction equation will be as follows.
So, cancelling the spectator ions then the equation will be as follows.
As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.
Rate law = ![k[H_{2}O_{2}][I^{-}]](https://tex.z-dn.net/?f=k%5BH_%7B2%7DO_%7B2%7D%5D%5BI%5E%7B-%7D%5D)
Hence, the reaction is first order with respect to ![[I^{-}]](https://tex.z-dn.net/?f=%5BI%5E%7B-%7D%5D)
and it is also first order reaction with respect to ![[H_{2}O_{2}]](https://tex.z-dn.net/?f=%5BH_%7B2%7DO_%7B2%7D%5D)
.
Also, acts as a catalyst in the reaction.
Thus, we can conclude that the incorrect statement is 
is a catalyst.
