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Elena L [17]
3 years ago
7

Explain how the following changes would affect the rate of the reaction of 2-bromo-3-methylbutane with methanol: Part A The alky

l halide is changed to 2-chloro-3-methylbutane. The alkyl halide is changed to 2-chloro-3-methylbutane. The reaction will be slower because the leaving group will be poorer. The reaction will be slower because the leaving group will be better. The reaction will be faster because the leaving group will be better. The rate of the reaction does not change.
Chemistry
1 answer:
swat323 years ago
6 0

Answer:

The reaction will be slower because the leaving group will be poorer.

Explanation:

One Important thing to put at the back of our mind is that weak bases are good leaving groups. Another thing to take note is that in the halogen series(which is our main subject in this question) as you go down the group the greater or the more heavy the halide is and the heavier halides are more stable that is Bromine will be more stable than chlorine.

Now, we are now told that the bromo halide is been replaced by the chloro halide which means that the rate of Reaction will surely decrease because the leaving group. The cl^- is a stronger base.

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UkoKoshka [18]

Answer:

Colourless

Explanation:

We know that Y^3+ has the electronic configuration of;

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 (the 5s and 4d levels are empty).

According to the crystal field theory, the colour of complexes result from transitions between incompletely filled d orbitals.

As a result of this, complexes with empty or completely filled d orbitals are colourless. Thus,  [Y(H2O)6]3 is colourless according to the Crystal Field Theory.

4 0
3 years ago
PLEASE HELP ME WITH MY CHEM TEST
fgiga [73]

Answer:

8. 0.96

9. d

10b

11. 3

12 d

Explanation:

4 0
3 years ago
1 How is the density of a substance calculated? 
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4 0
3 years ago
37.5g of nitrogen reacts with 15.5 g of hydrogen. What mass of ammonia can be made? What is the limiting reactant?
Gennadij [26K]

Answer:

Limiting reactants or limiting reagents decide the amount of product formed and the amount of excess reagent used.

7 0
3 years ago
someone pls help me with my chemistry test plsss my teacher changes the questions so I can't search them up. its 21 questions so
shusha [124]

Answer:

Correct option is

B

5 liters of CH

4

(g)NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

7 0
2 years ago
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