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VashaNatasha [74]
3 years ago
14

Calculate the mass defect of the helium nucleus 32he. the mass of neutral 32he is given by mhe=3.016029amu. express your answer

in atomic mass units to four significant figures.
Physics
1 answer:
Romashka [77]3 years ago
4 0
Answer: 0.007044 g

Explanation:

1) mass defect is the difference between the mass of the nucleus and the sum of the masses of the protons and neutrons.

3) He has two protons.

4) The istope given is ³₂ He, which means it has 2 protons and 1 neutron.

5) The masses of neutrons and protons are taken from a table (from a textbook or the internet)

Mass of 2 mol of protons: 2 × 6.022 × 10 ²³ protons/mol × 1.6726 × 10 ⁻²⁴ g/mol = 2.014447944 g

Mass of 1 mol of neutrons = 1 × 6.022 × 10²³ neutrons/mol × 1.6749 × 10 ⁻²⁴ g/mol = 1.00862478 g

Sum = 2.014447944 g + 1.00862478 g = 3.023072724 g

6) mass deffect = 3.023072724g - 3.016029 g = 0.007043724

7) Round to 4 significant figures: 0.007044 g

That is the answer: 0.007044 g


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You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be
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Answer:

The amplitude  is  A =  90.2 \ m

Explanation:

From the question we are told that

    The frequency of when sound is approaching observer is   f = 392 Hz

     The frequency as the move away from observer  is  f_ a =  330 \ Hz

    The time between the pitch are t =  10 \ s

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

       T =  2 t

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

          T = \frac{2 \pi}{w}

Where  w is the angular velocity

=>   \frac{2 \pi}{w}  =  2 * 10

=>   w =  0.314 \ rad/sec

Now using Doppler Effect,

   The source of the sound is approaching the observer

The

          f = f_o (\frac{v}{v- wA} )

         392  = f_o (\frac{v}{v- wA} )

Where A is the amplitude

    So when the source is moving away from the observer

         f_a =  f_o (\frac{v}{v+ wA} )  

        330  =  f_o (\frac{v}{v+ wA} )  

Here  f_o is the fundamental frequency

Dividing the both equation  we have

           \frac{392}{330}  =  \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}

           1.1878  = \frac{v+wA}{v-wA}

         1.1878 v -  1.1878 wA = v+wA

        1.1878 v = 2.1878 wA

=>     A =  \frac{(0.1878 * (330))}{(2.1878)* (0.314)}

         A =  90.2 \ m

7 0
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Answer: 68852 millijoules = 16.46 calories

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Therefore,

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68852 millijoule = 68852 × 1/4184 calories

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