A 2640-Hz sound source is moving at 15.0m/s toward a stationary observer. What is the frequency heard by the observer if the spe
1 answer:
Answer:
The frequency heard by the observer is 2760.73 hertz. Explanation:
Frequency of source, f = 2640 Hz
Velocity of source,
The speed of sound, v = 343 m/s
Let f' is the frequency heard by the observer. According to Doppler's effect, the frequency of the observer is given by :
(as the source is moving towards observer)
f' = 2760.73 Hz
So, the frequency heard by the observer is 2760.73 hertz. Hence, this is the required solution.
You might be interested in
PH measures the concentration of hydrogen ions (
) in a solution. Knowing this, you can determine how acidic -or basic- your solution is.
Answer:
6.48*10⁻⁷ C
Explanation:
- By definition, the capacitance of a capacitor is expressed as follows:
- where Q is the charge on one of the plates of the capacitor, and V the potential difference between the plates.
- The maximum electric field, the potential difference, and the distance between plates are related by the following expression:
- Replacing by the givens, we can find V as follows:
- Now, we can find the maximum charge Qmax, as follows:
- The maximum charge that the capacitor can hold is 6.48*10⁻⁷ C.