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zaharov [31]
3 years ago
12

Can someone plz help. Define solubility

Chemistry
1 answer:
ANEK [815]3 years ago
3 0

Amount of a substance (called the solute) that dissolves in a unit volume of a liquid substance (called the solvent) to form a saturated solution under specified conditions of temperature and pressure. Solubility is expressed usually as moles of solute per 100 grams of solvent.

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PLEASEEEE HELLPPP I CANT FAILL PLSS
sdas [7]
It’s the second won the air layer one
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How many valence electrons does each of the following atoms have?
Zolol [24]
Which atoms?  ~~~~~~~~~~~~~~~~~~~~~~~~~`
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4 years ago
Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th
Vera_Pavlovna [14]

Answer:

[H^+]=0.000285

pH=3.55

Explanation:

In this, we can with the <u>ionization equation</u> for the hydrazoic acid (HN_3). So:

HN_3~~H^+~+~N_3^-

Now, due to the Ka constant value, we have to use the whole equilibrium because this <u>is not a strong acid</u>. So, we have to write the <u>Ka expression</u>:

Ka=\frac{[H^+][N_3^-]}{[HN_3]}

For each mol of H^+ produced we will have 1 mol of N_3^-. So, we can use <u>"X" for the unknown</u> values and replace in the Ka equation:

Ka=\frac{X*X}{[HN_3]}

Additionally, we have to keep in mind that HN_3 is a reagent, this means that we will be <u>consumed</u>. We dont know how much acid would be consumed but we can express a<u> subtraction from the initial value</u>, so:

Ka=\frac{X*X}{0.004-X}

Finally, we can put the ka value and <u>solve for "X"</u>:

2.2X10^-^5=\frac{X*X}{0.004-X}

2.2X10^-^5=\frac{X^2}{0.004-X}

X= 0.000285

So, we have a concentration of 0.000285 for H^+. With this in mind, we can calculate the <u>pH value</u>:

pH=-Log[H^+]=-Log[0.000285]=3.55

I hope it helps!

8 0
3 years ago
The air inside a bicycle tire pump has 27 joules of heat conducted away from while 77.9 joules of work done are being done on it
tatyana61 [14]

Answer:

51 J

Explanation:

The air inside a bicycle tire pump has 27 joules of heat conducted away. By convention, when heat is released, it takes the negative sign, so Q = -27 J.

77.9 joules of work done are being done on the air inside a bicycle tire pump. By convention, when work is being done on the system, it takes the positive sign, so W = 77.9 J

We can calculate the change in the internal energy (ΔU) using the following expression.

ΔU = Q + W

ΔU = (-27 J) + 77.9 J

ΔU =  51 J

7 0
3 years ago
How do the number of electrons in the second energy shell of an atom change going across period 2 in the periodic table?
weqwewe [10]
The answer should be A, the number of electrons increases by 1, from left to right.

Across the periods (horizontal direction) in periodic table, each element has one more electron then the one before it. The number of period determines the number of occupied electron shells of the elements in that period. Which means, period 1 elements have 1 occupied electron shell, period 2 has 2, period 3 has 3 etc.

Therefore, the answer is A, we always go from left to right, and plus since period 2 elements only have 2 occupied electrons so their 2nd electron shell electrons must increase throughout the period.
8 0
3 years ago
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