We are given to lines XY and VW. Now we need to determine the expression that correctly states that these lines are congruent. One possibility to prove that they're congruent is if they are two separate lines and:
XA is congruent to VB,
AY is congruent to BW
XA + AY = XY
VB + BW = VW
Then we can conclude that if the statements above are true, XY and VW must be congruent to each other.
Another possibility is that they are two sides of an isosceles rectangle XYVW and are opposite sides of the rectangle. <span />
3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15
Answer:
Option a)
Step-by-step explanation:
To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.
Then. x = 2 it's a vertical asintota.
To obtain the horizontal asymptote of the function take the following limit:
if then y = b is horizontal asymptote
Then:
Therefore y = 0 is a horizontal asymptote of f(x).
Then the correct answer is the option a) x = 2, y = 0
Answer:
132 mm^2
Step-by-step explanation:
The line added to the figure in the attachment shows it can be divided into two figures whose area is easily calculated.
1. A parallelogram of base length 20 mm and height 4 mm:
A = bh = (20 mm)(4 mm) = 80 mm^2
2. A trapezoid with bases 32 mm and 20 mm, and height 2 mm:
A = (1/2)(b1 +b2)h = (1/2)(32 mm +20 mm)(2 mm) = 52 mm^2
The total area of the figure is then ...
80 mm^2 +52 mm^2 = 132 mm^2