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3 years ago

FORENSIC SCIENCE--

Physics

1 answer:

nikklg [1K]3 years ago

7 0

Answer:

D. 90

Explanation:

because even if there is a shadow of doubt the person should not be persecuted as it could lead to false imprisonment

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An object has a coefficient of kinetic friction of 0.2 and a normal force of 30N. Find the force of kinetic friction.

shutvik [7]

Answer:

Force of kinetic friction, Fk = 6N

Explanation:

Given the following data;

Coefficient of kinetic friction, μ = 0.2

Normal force, Fn=30N

To find the Force of kinetic friction;

Mathematically, the force of kinetic friction is given by the formula;

Fk = μFn

Where;

Fk represents the force of kinetic friction.

μ represents the coefficient of friction.

Fn represents the normal force.

Substituting into the equation, we have;

Fk = 0.2*30

Fk = 6N

Therefore, the force of kinetic friction is 6N.

6 0

3 years ago

One and one-half moles of an ideal monatomic gas expand adiabatically, performing 7900 J of work in the process. What is the cha

mart [117]

Answer:

The temperature change is -633.15K

Explanation:

If we considered the expansion as a reversible one (to be adiabatic is one of the requirements), the work done by expansion can be written as:

$W=-n*P(v_2-v_1)=-P*(V_2-V_1)$ Where 2 and 1 subscripts mean the final and the initial state respectively. The equation negative sign says that for an expansion of the gas, the system is making work, so the energy is going out of the system.

Using the ideal gas equation, it is possible to change volume and pressure by temperatures:

$PV_2=(nRT_2)\\PV_1=nRT_1$

So,

$W=-nR(T_2-T_1)$

$(T_2-T_1)=\frac{-W}{nR}=\frac{-7900J}{(1.5mol*8.314\frac{J}{molK})}=-633.5K$

This result makes sense considering that the volume increases, so it is expected that the temperature decreases.

4 0

3 years ago

A plane is flying east at 135 m/s. The wind accelerates it at 2.18 m/s2 directly northeast. After 18.0 s, what is the direction

Brrunno [24]

the plane was flying at 2,691. 33 m at 5.32°

4 0

3 years ago

Select the correct scientific notation form of this numeral. 106.3

Alja [10]

Scientfic notation 1.063 x 10^2

5 0

4 years ago

Suppose the moon were held in its orbit not by gravity but by the tension in a massless cable. You are given that the period of

Ksenya-84 [330]

Answer:

Tension in the cable = 200.655 × 10^(18) N

Explanation:

The tension in the cable will be the force on the string which is caused by when it holds against the centripetal acceleration.

Now, the formula for centripetal acceleration is given by;

a = v²/R

Now, let's find the velocity.

The circumference is 2πR

We are given that R = 3.85 x 10^(8) m

So, Circumference = 2 × π × 3.85 x 10^(8) = 24.19 × 10^(8) m

We are told the period of the moon orbit is 27.3 days

Distance travelled per day = Circumference/ period

Distance travelled per day = (24.19 × 10^(8))/27.3 = 88608058.608 m/day

Now, a day has 24 hours = 24 × 60 × 60 = 86400 seconds

Thus,

Distance travelled per seconds =

88608058.608/86400 = 1025.556 m/sec

So, from a_c = v²/r,

a_c = 1025.556²/3.85x10^8

a_c = 0.00273 m/s²

Now, Force = Mass x Acceleration = ma

We are given mass = 7.35 x 10^(22) kg

Plugging in the relevant values, we have;

F = 0.00273 x 7.35 x 10^(22)

F = 200.655 × 10^(18) N

5 0

3 years ago