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Elza [17]
2 years ago
8

.・✫・゜・。.

Physics
2 answers:
Vaselesa [24]2 years ago
8 0

Answer:

• External unbalanced forces help to overcome the inertia of the object.

• The dust particles that were previously at rest on the carpet remain at rest due to their inertia and hence, get separated from the carpet. This is why when a carpet is beaten with a stick, dust comes out from it.

Mrac [35]2 years ago
5 0

Answer:

because dust particles wants to stay in rest but when we hit or beat carpet it comes in motion and due to unbalanced inertia it's fall down..

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Present the ways to observe interference patterns on thin films. Why the thickness of thin films should be in scale of wavelengt
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Answer:

A colorful interference pattern is observed when light is reflected from the top and bottom boundaries of a thin oil film. The different bands form as the film's thickness diminishes from a central run-off-poin

Explanation:

<h3>hope it help brainliest pls</h3>
5 0
3 years ago
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The granulation pattern that astronomers have observed on the surface of the Sun tells us that: a. the Sun is a lot cooler on th
Norma-Jean [14]

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c. hot material must be rising from the Sun's hotter interior

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3 years ago
Which Quantity is a vector Quantity?<br><br> A] Acceleration<br> B] Mass<br> C] Speed<br> D] Volume
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4 0
3 years ago
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A neutral solid metal sphere of radius 0.1 m is at the origin, polarized by a point charge of 2 × 10−8 C at location m. At locat
liraira [26]

Answer: E = 1.8 *10 ^{4} N

Explanation: The formulae for intensity of an electric field of a solid metal sphere relative to a point is given below

E =\frac{Kq}{r^{2} } r

where  k=9* 10^{9}N/m^{2}, q=2 *10 ^{-8} c , r = 0.1m r = is the position vector of the charge.

it has been stated in the question that the charge is placed at the center thus it has no position vector.

E=\frac{9 * 10^{9}* 2* 10^{-8}  }{0.1^{2} }\\ =\frac{18* 10^{1} }{0.01} \\=\frac{18* 10^{1} }{1 *10^{-2} } = 1.8*10^{4} N

6 0
3 years ago
If the mean velocity adjacent to the top of a wing of 1.8 m chord is 40 m/s and that adjacent to the bottom of the wing is 31 m/
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lift per meter of span = 702 N/m

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See attached pictures.

7 0
4 years ago
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