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coldgirl [10]
3 years ago
11

What is the measure of angle 7?

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

The measure of angle 7 is 155*.

Step-by-step explanation:

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i don’t understand what ? is. it’s pythagorean theorem and i know for this question, you HAVE to add, but i always get an answer
Sophie [7]

P1 = 10 m²

P2 = 22 m²

P3 = ?

According to Pythagoras' theorem:

P1 + P2 = P3

P3 = 10 m² + 22 m² = 32 m²

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3 years ago
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Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
FIND THE SURFACE AREA OF PYRAMID (HELP!)
ollegr [7]
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2 years ago
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kodGreya [7K]
A. If there are only green and yellow M & M’s in the bag, what is the smallest number of
M & M’s possible? 7 M & M’s total
b. If there are 84 M & M’s in the bag all together, how many are green? 24 green ones
c. If red M & M’s were added to the bag in part b to get a total of 100, what is the ratio of green to yellow to red? 6: 15: 4
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3 years ago
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A bowl has 9 green grapes and 13 grapes. Henry randomly chooses a grape, and eats it, and then choose a another grape What is th
Sunny_sXe [5.5K]

Answer:

\frac{72}{462} or \frac{12}{77} (simplified)

Step-by-step explanation:

Based on the information provided within the question it can be said that in order to calculate the probability of both grapes being green we need to find the probability of each grape being green separately and then multiply those probabilities together

In the first choice, there are a total of 22 grapes (9+13), 9 of which are green. Therefore the probability of the first chosen grape being green is \frac{9}{22}

In the second choice,since we removed one grape there is now a total of 21 grapes (22-1), 8 of which are green. Therefore the probability of the second chosen grape being green is \frac{8}{21}

Now we multiply both probabilities together to calculate the probability that both grapes are green in a sequence.

\frac{9}{22} * \frac{8}{21}  = \frac{72}{462} or \frac{12}{77}

7 0
3 years ago
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